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IgorLugansk [536]
3 years ago
13

Tara has 3/4 cup of ice cream. How many 1/5 -cup servings are in 3/4 cup of ice cream?​

Mathematics
1 answer:
saw5 [17]3 years ago
8 0

Answer:

4/15

Step-by-step explanation:

because 1/5÷3/4=4/15

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Find the midpoint of the line segment whose endpoints are (3, 10) and (7, 8).
Stels [109]

Answer:

Option 2 is correct.

Step-by-step explanation:

Given the coordinates of lines segment (3, 10) and (7, 8). we have to find the mid-point of given line segment.

Mid-point formula states that if (x_1,y_1) and (x_2,y_2) are the coordinates of end points of line segment then the coordinates of mid-point are

(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

∴ Coordinates of mid-point of line segment joining the points          (3, 10) and (7, 8) are

(\frac{3+7}{2},\frac{10+8}{2})=(\frac{10}{2},\frac{18}{2})=(5,9)

Hence, option 2 is correct.

6 0
2 years ago
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Solve for x <br> -4&lt;11-3x<br> ( the picture are the answer choices)
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It is number 2 k mate
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Which fraction is multiple of 1/10
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2/20 thats one i got for now
3 0
3 years ago
Find the area under the standard normal probability distribution between the following pairs of​ z-scores. a. z=0 and z=3.00 e.
prohojiy [21]

Answer:

a. P(0 < z < 3.00) =  0.4987

b. P(0 < z < 1.00) =  0.3414

c. P(0 < z < 2.00) = 0.4773

d. P(0 < z < 0.79) = 0.2852

e. P(-3.00 < z < 0) = 0.4987

f. P(-1.00 < z < 0) = 0.3414

g. P(-1.58 < z < 0) = 0.4429

h. P(-0.79 < z < 0) = 0.2852

Step-by-step explanation:

Find the area under the standard normal probability distribution between the following pairs of​ z-scores.

a. z=0 and z=3.00

From the standard normal distribution tables,

P(Z< 0) = 0.5  and P (Z< 3.00) = 0.9987

Thus;

P(0 < z < 3.00) = 0.9987 - 0.5

P(0 < z < 3.00) =  0.4987

b. b. z=0 and z=1.00

From the standard normal distribution tables,

P(Z< 0) = 0.5  and P (Z< 1.00) = 0.8414

Thus;

P(0 < z < 1.00) = 0.8414 - 0.5

P(0 < z < 1.00) =  0.3414

c. z=0 and z=2.00

From the standard normal distribution tables,

P(Z< 0) = 0.5  and P (Z< 2.00) = 0.9773

Thus;

P(0 < z < 2.00) = 0.9773 - 0.5

P(0 < z < 2.00) = 0.4773

d.  z=0 and z=0.79

From the standard normal distribution tables,

P(Z< 0) = 0.5  and P (Z< 0.79) = 0.7852

Thus;

P(0 < z < 0.79) = 0.7852- 0.5

P(0 < z < 0.79) = 0.2852

e. z=−3.00 and z=0

From the standard normal distribution tables,

P(Z< -3.00) = 0.0014  and P(Z< 0) = 0.5

Thus;

P(-3.00 < z < 0 ) = 0.5 - 0.0013

P(-3.00 < z < 0) = 0.4987

f. z=−1.00 and z=0

From the standard normal distribution tables,

P(Z< -1.00) = 0.1587  and P(Z< 0) = 0.5

Thus;

P(-1.00 < z < 0 ) = 0.5 -  0.1586

P(-1.00 < z < 0) = 0.3414

g. z=−1.58 and z=0

From the standard normal distribution tables,

P(Z< -1.58) = 0.0571  and P(Z< 0) = 0.5

Thus;

P(-1.58 < z < 0 ) = 0.5 -  0.0571

P(-1.58 < z < 0) = 0.4429

h. z=−0.79 and z=0

From the standard normal distribution tables,

P(Z< -0.79) = 0.2148  and P(Z< 0) = 0.5

Thus;

P(-0.79 < z < 0 ) = 0.5 -  0.2148

P(-0.79 < z < 0) = 0.2852

8 0
2 years ago
(x/16)-(x+2)/8))=2<br><br><br><br> PLS HELP ME BRAINLIEST TO THE FIRST CORRECT ANSWER
ArbitrLikvidat [17]

Simplify both sides of the equation

x/16−(x+2/8) = 2x/16 + −1/8x + −1/4 = 2

Distribute

1/16x + −1/8x + −1/4 = 2

(1/16x + −1/8x)+(−1/4) = 2

Combine Like Terms

−1/16x + −1/4 = 2

Add 1/4 to both sides.

−1/16x + −1/4 + 1/4 = 2 + 1/4

−1/16x = 9/4

Multiply both sides by 16/(-1).

(16/−1)*(−1/16x)=(16/−1)*(9/4)

x=−36

3 0
2 years ago
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