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GarryVolchara [31]
3 years ago
14

Which point on the graph shows the amount of water in the bucket after 1 second? Hint: Type your answer in the form (x coordinat

e, y coordinate).
plz answer.

Mathematics
1 answer:
Taya2010 [7]3 years ago
6 0

Answer:

\displaystyle \left(1,\frac{5}{12}\right)

Step-by-step explanation:

<u>Graphs</u>

The graph shows the amount of water in gallons as a function of time in seconds.

We are required to find the amount of water in the bucked after 1 second. Since the graph does not show an exact location for t=1, we must find the equation of the line.

Two points are clear on the graph: (0,0) (12,5). This gives us the necessary information to find the equation of the line, which has the form:

w=mt+b

Where w is the amount of water in the bucket, t is the time, and m and b are two constants to be determined.

Using the point (0,0):

0=m(0)+b

It follows that b=0

The equation now takes the form:

w=mt

Using the point (12,5):

5=m(12)

We find m:

\displaystyle m=\frac{5}{12}

The final equation is:

\displaystyle w=\frac{5}{12}\cdot t

Substituting t=1:

\displaystyle w(1)=\frac{5}{12}\cdot (1)=\frac{5}{12}

The bucket has 5/12 gallons of water at t=1 second. Expressing the answer as an ordered pair:

\boxed{\displaystyle \left(1,\frac{5}{12}\right)}

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tiny-mole [99]
(-3)+(5)+(-3)=-1
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5 0
2 years ago
Solve: a + 4 = 48<br> a = 43<br> a = 51<br> a = 44<br> a = 52
andrew11 [14]

Answer:

a = 44 is correct

Step-by-step explanation:

a + 4 = 48

plug in the #'s 1 at a time

43 + 4 = 48

47 = 48  FALSE

51 + 4 = 48

55 = 48  FALSE

44 + 4 = 48  TRUE

52 + 4 = 48  FALSE

Hope this Helps!!!

5 0
3 years ago
The function y = sin 2 (x – π∕2) has a period of Question 2 options: A) 4π. B) π. C) 2π. D) π∕2.
masya89 [10]

Answer:

B) π

Step-by-step explanation:

y = sin 2 (x – π∕2)

y = sin (2x -π)

=> 2x = 2π

x = π

5 0
2 years ago
PLEASE HELP!!! (WILL GIVE BRAINLIEST FOR CORRECT ANSWER :)
cestrela7 [59]
-180 is the answer
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7 0
2 years ago
In a home theater system, the probability that the video components need repair within 1 year is 0.02, the probability that the
earnstyle [38]

Answer:

(a) The probability that at least one of these components will need repair within 1 year is 0.0278.

(b) The probability that exactly one of these component will need repair within 1 year is 0.0277.

Step-by-step explanation:

Denote the events as follows:

<em>A</em> = video components need repair within 1 year

<em>B</em> = electronic components need repair within 1 year

<em>C</em> = audio components need repair within 1 year

The information provided is:

P (A) = 0.02

P (B) = 0.007

P (C) = 0.001

The events <em>A</em>, <em>B</em> and <em>C</em> are independent.

(a)

Compute the probability that at least one of these components will need repair within 1 year as follows:

P (At least 1 component needs repair)

= 1 - P (No component needs repair)

=1-P(A^{c}\cap B^{c}\cap C^{c})\\=1-[P(A^{c})\times P(B^{c})\times P(C^{c})]\\=1-[(1-0.02)\times (1-0.007)\times (1-0.001)]\\=1-0.97216686\\=0.02783314\\\approx 0.0278

Thus, the probability that at least one of these components will need repair within 1 year is 0.0278.

(b)

Compute the probability that exactly one of these component will need repair within 1 year as follows:

P (Exactly 1 component needs repair)

= P (A or B or C)

=P(A\cap B^{c}\cap C^{c})+P(A^{c}\cap B\cap C^{c})+P(A^{c}\cap B^{c}\cap C)\\=[0.02\times (1-0.007)\times (1-0.001)]+[(1-0.02)\times 0.007\times (1-0.001)]\\+[(1-0.02)\times (1-0.007)\times 0.001]\\=0.02766642\\\approx 0.0277

Thus, the probability that exactly one of these component will need repair within 1 year is 0.0277.

7 0
3 years ago
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