For this case we have the following equation:
V = I * R
Where,
V: voltage
I: current
R: resistance
By clearing R we have:
R = V / I
Substituting the values:
R = (20) / (0.57)
R = 35.09 Ohms
Answer:
The resistance of the light bulb is:
R = 35.09 Ohms
<span>2. scalene, isosceles, equilateral</span>
Answer:
$67,580.73
Step-by-step explanation:
$49,329÷100=$493.29 (1%)
$493.29×37=$18,251.73 (37%)
$49,329+$18,251.73=$67,580.73
First subtract 2 revolutions from the - 840 :- (- (840-720) = -120
This gives sin -120 which is in the 3rd quadrant of the unit circle
sin -120 = - sin 60 = - sqrt3/2
Answer:
the correct answer is the 3rd one