**30 points*** PLEASE ASSIST WILL GET BRAINIEST I REALLY NEED HELP!!!
1 answer:
Answer:
let the equal sides of the triangle be of length "a" . let the angle between these two sides be " x ". Then drop a perpendicular from the vertex to the base. now u have 2 similar triangles .the angle between the perpendicular and one of the equal sides is now (x/2) . length of perpendicular = a cos(x/2) length of base = 2a sin(x/2) . area of triangle = (1/2) 2sin(x/2) cos(x/2) a-square
= (1/2) (sin x) a-square
You might be interested in
A cube is a 3 dimensional object with 6 square faces. All its sides are the same length, there fore the volume is equal to 
where s is the side length.
To solve for s, take the cube root of both sides.
![\sqrt[3]{s^3}= \sqrt[3]{ \frac{27}{64} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bs%5E3%7D%3D%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B27%7D%7B64%7D%20%7D%20%20)
feet
To solve for s, take the cube root of both sides.