Answer:
1,778
Step-by-step explanation:
Let C and S represent the cost and salvage value of Truck B, respectively. Let X represent the number of miles per year that answers the question.
Truck A's cost for 10 years is ...
A = C+600 +(0.06)(2.25)(10X) -(S+200)
Truck B's cost for 10 years is ...
B = C +(0.07)(2.25)(10X) -S
We want to find X such that Truck A's cost is lower, so ...
C -S +1.35X +400 < C -S +1.575X
400 < 0.225X
1777 7/9 < X
1778 miles driven per year (or more) makes Truck A a better option.
Answer:
Step-by-step explanation:
Given
![A = \left[\begin{array}{cc}-2&6\\3&5\end{array}\right]](https://tex.z-dn.net/?f=A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-2%266%5C%5C3%265%5Cend%7Barray%7D%5Cright%5D)
Required
Determine the determinant
For a two by two matrix, A such that:
![A = \left[\begin{array}{cc}a&b\\c&d\end{array}\right]](https://tex.z-dn.net/?f=A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Da%26b%5C%5Cc%26d%5Cend%7Barray%7D%5Cright%5D)
The determinant |A| is:
So, in
The determinant is:
Answer:
it is 2mm long
Step-by-step explanation:
16x0.125=2 so it is 2mm long
