Only a 2 minute job pls help ;/ even if u can only do 1 it wud be gladly appreciated

AKAJAXOSPAPXODAOAPA HELP

Leya [2.2K]

Answer:

He used 6 bananas at .50 which cost $3.00

12 oranges at .75 which cost $9.00 and

3 papayas at $1.25 which cost $3.75

Step-by-step explanation:

We can set up a system of equations using the information given.

b for banana, r for orange, p for papaya

b + r + p = 21. Also given r = 2b So substitute to simplify for calculating two unknowns:

b + 2b + p = 21 The number of items.

50b + 75(2b) +125p = 1575 The cost.

I multiplied everything by 100 to eliminate the decimals.

To solve by substituion, rewrite the first equation to get a value for p in terms of b

p = 21 - 3b

Substitute this value in the second equation and solve for b.

50b + 150b + 125(21–3b) = 1575

200b +2625 –375b = 1575 Subtract 2625 from both sides and combine the like terms:

–175b = 1575 –2625

–175b = –1050. Divide both sides by –175

b = 6

Substitute in the original equation to find the amount of each fruit:

b + r + p = 21

b = 6 bananas

r = 2b. 2(6) = 12 oranges. I used r so as not to mix up o with 0.

6 + 12 + p = 21

p = 21 –18

p = 3 papayas

7 0

2 years ago

Let point L be between M and N on MN. Given that MN=31, ML= h-15 and LN = 2h-8. Find LN.

shtirl [24]

Given that point L is between M and N on MN. Then
MN = ML + LN
31 = h - 15 + 2h - 8 = 3h - 23
3h = 31 + 23 = 54
h = 54/3 = 18

Therefore, LN = 2(18) - 8 = 36 - 8 = 28.

8 0

3 years ago

Challenge question please help

Pani-rosa [81]

Answer:

The 3 possible values of x are;

6, 4 and 2

Step-by-step explanation:

If the triangle is isosceles, then two of the sides must be equal

So we equate the sides, 2 at a time to get the different values of x

3x + 4 = 2x + 10

3x-2x = 10-4

x = 6

3x + 4 = x + 12

3x-x = 12-4

2x = 8

x = 8/2 = 4

2x + 10 = x + 12

2x - x = 12-10

x = 2

7 0

3 years ago

Plz help me on this

Margarita [4]

$125.4 is the answer to #1
#2 im not sure how the 10% effects the problem. so i cant help you there

7 0

2 years ago

What is the sum or difference?

dlinn [17]

1. Ans: Option (B) $-6x^4$

Explanation:
Given: $2x^4 - 8x^4$
Take the common out:
=> $x^4(2 - 8)$

Hence: => $[tex]-6x^4$ [/tex] (Option B)

2. Ans: Option (D) $-3y^5$

Explanation:
Given: $6y^5 - 9y^5$
Take the common term(s) out:
=> $y^5(6-9)$

Hence: => $-3y^5$ (Option D)

3. Ans: Option (B) $9x^2 - 12x + 6$ quadratic trinomial

Explanation:
Given: $6 - 12x + 13x^2 - 4x^2$

The standard form of polynomial function must have the highest powered value at the start, then the second highest and so on.

=> $13x^2 - 4x^2 - 12x + 6$
=> $9x^2 - 12x + 6$ (Option B)

4. Ans: Option (C) $7.3x^2 + 0.8x + 1.3$

Explanation:
In order to find the total number of Common and Endler's guppies, you need to add both Common and Endler's guppies' polynomials, as follows:

Common guppies: $3.1x^2 +6.0x + 0.3$ 
Endler's guppies: $4.2x^2 - 5.2x + 1.0$
(add both)
-----------------------------------------------------------------
Total number: $7.3x^2 +0.8x + 1.3$
-----------------------------------------------------------------
Hence the ans is Option(C) $7.3x^2 + 0.8x + 1.3$

5. Ans: Option (D) $2x^2(133 - 18 \pi )$

Explanation:
First let's find the total area of the yard:
Total Area of the Yard = 14x * 19x = $266x^2$

Now the area of the circular fountain:
Area of the Circular Fountain = $\pi r^2$
Since, r=6x
Therefore,
Area of the Circular Fountain = $\pi (6x)^2 = 36 \pi x^2$

Now the final Area of the yard would be:
Final area of the Yard = Total Area of the Yard - Area of the Circular Fountain
Final area of the Yard = $266x^2$ - $36 \pi x^2$
=> Final area of the Yard = $2x^2(133 - 18 \pi)$ (Option D)

6. Ans: Option (A) $56x^2$

Explanation:
First let's find the total area of the lot:
Total Area of the lot= 6x * 10x = $60x^2$

Now the area of the stadium:
Area of the stadium = 1x * 4x = $4x^2$

Now the final Area of the lot would be:
Final area of the lot= Total Area of the lot - Area of the stadium
Final area of the lot= $60x^2$ - $4x^2$
=> Final area of the lot = $56x^2$ (Option A)

-i

4 0

3 years ago

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