Answer:
The correct Answer is 0.0571
Explanation:
53% of U.S. households have a PCs.
So, P(Having personal computer) = p = 0.53
Sample size(n) = 250
np(1-p) = 250 * 0.53 * (1 - 0.53) = 62.275 > 10
So, we can just estimate binomial distribution to normal distribution
Mean of proportion(p) = 0.53
Standard error of proportion(SE) = 
= 
= 0.0316
For x = 120, sample proportion(p) = 
= 
= 0.48
So, likelihood that fewer than 120 have a PC
= P(x < 120)
= P( p^ < 0.48 )
= P(z < 
) (z=
)
= P(z < -1.58)
= 0.0571 ( From normal table )
Answer:Start with the algorithm you are using, and phrase it using words that are easily transcribed into computer instructions.
Indent when you are enclosing instructions within a loop or a conditional clause Avoid words associated with a certain kind of computer language.
Explanation:
Answer: A) Installed
Explanation: Installed application work on the system on which they are installed .They are supposed to persist the required speed of processing to execute the task ,enough memory and other resources as well to fulfill the need of the application functioning.
Other option is incorrect because cloud based application run with help of internet service via web browser so they resources in this applications based on the internet connectivity and browser's speed .Thus, the correct option is option(A).
