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scoray [572]
3 years ago
13

What is the equation of the line that passes through (-2,4) (-6,10)

Mathematics
1 answer:
Nata [24]3 years ago
7 0

Answer:

\large\boxed{y-4=-\dfrac{3}{2}(x+2)}\to\boxed{y=-\dfrac{3}{2}x+1}\to\boxed{3x+2y=2}

Step-by-step explanation:

The point-slope form of an equation of a line:

y-y_1=m(x-x_1)

m - slope

m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (-2, 4) and (-6, 10). Substitute:

m=\dfrac{10-4}{-6-(-2)}=\dfrac{6}{-4}=-\dfrac{6}{4}=-\dfrac{3}{2}\\\\y-4=-\dfrac{3}{2}(x-(-2))\\\\y-4=-\dfrac{3}{2}(x+2)

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