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NISA [10]
3 years ago
7

What's the degree of the polynomial? P(x)= 7x^7+2x^5+7x+7

Mathematics
1 answer:
mario62 [17]3 years ago
4 0

Answer:

7

General Formulas and Concepts:

  • Degree of Polynomial is determined by the highest power

Step-by-step explanation:

<u>Step 1: Define function</u>

P(x) = 7x⁷ + 2x⁵ + 7x + 7

<u>Step 2: Identify</u>

7x⁷ is the largest term.

  • Has the highest power
  • Therefore, highest degree
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Solve the following quadratic equation by using the quadratic formula.
Bas_tet [7]

Answer:

B. \frac{-3}{4}±\frac{\sqrt{41} }{4}

Step-by-step explanation:

First, substitute the equation into the quadratic formula.

x=\frac{b+-\sqrt{(b^{2} )-4(a)(c)} }{2a}

x=\frac{-3+-\sqrt{(3)^2-4(-2)(4)} }{4}

Solve for x.

x= \frac{-3+-\sqrt{9+32} }{4}

x=\frac{-3+-\sqrt{41} }{4}

The answer is x= -\frac{3}{4}±\frac{\sqrt{41} }{4}

6 0
3 years ago
What is the mode of this data set? 64°, 72°, 74°, 68°, 70°, 68°, 68°, 75°, and 44
butalik [34]

Hey there!

Mode is basically the number you see more than once,

64, 72, 74, 68, 70, 68, 68, 75,  44\\ \\ Mode: 68

Your answer would be: 68 because it appeared approximately 3 times in this data set

Good luck on your assignment and enjoy your day!

~LoveYourselfFirst:)

6 0
3 years ago
Read 2 more answers
10.5125 rounded to the nearest cent plz help me ty &lt;3
Phoenix [80]

Answer: your answer should be 10.5130

Step-by-step explanation:

5 0
3 years ago
At 2:00 PM a car's speedometer reads 30 mi/h. At 2:15 PM it reads 50 mi/h. Show that at some time between 2:00 and 2:15 the acce
g100num [7]

Here is the correct format for the question

At 2:00 PM a car's speedometer reads 30 mi/h. At 2:15 PM it reads 50 mi/h. Show that at some time between 2:00 and 2:15 the acceleration is exactly 80 mi/h².Let v(f) be the velocity of the car t hours after 2:00 PM.Then \dfrac{v(1/4)-v(0)}{1/4 -0} = \Box. By the Mean Value Theorem, there is a number c such that 0 < c < \Box  with v'(c) = \Box. Since v'(t)  is the acceleration at time t, the acceleration c hours after 2:00 PM is exactly 80 mi/h^2.

Answer:

Step-by-step explanation:

From the information given :

At  2:00 PM ;

a car's speedometer v(0) = 30 mi/h

At 2:15 PM;

a car's speedometer v(1/4) = 50 mi/h

Given that:

v(f) should be the velocity of the car t hours after 2:00 PM

Then \dfrac{v(1/4)-v(0)}{1/4 -0} = \Box will be:

= \dfrac{50-30}{1/4 -0}

= \dfrac{20}{1/4 }

= 20 × 4/1

= 80 mi/h²

By the Mean value theorem; there is a number c such that :

\mathbf{0 < c< \dfrac{1}{4}}     with \mathbf{v'(c) = \dfrac{v(1/4)-v(0)}{1/4 -0}} \mathbf{ = 80 \ mi/h^2}

6 0
3 years ago
What does y equal y=-1+6
makvit [3.9K]

Answer:

5

Step-by-step explanation:

-1 + 6 = 5

4 0
3 years ago
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