Hello from MrBillDoesMath!
Discussion:
The slope of the tangent to the curve y = 4x^3 is given by the first derivative.
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y' = 4 (3x^2) = 12x^2
At (-3,-108), the slope is 12x^2 = 12(-3)^2 = 12*9 = 108
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y = mx + b
From the first part, m = 108 so y = 108x + b.
Substituting y = -108 when x = -3 gives
-108 = 108(-3) + b => add 3* 108 to both sides
-108 + 108(3) = b => as 3 -1 = 2
108*2 = b = 216
y = 108x + 216
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Thank you,
MrB
Answer: x = 10 and y = 3
Step-by-step explanation:
Due to the x rule, (5x - 17) = (3x + 3)
If we add 17 to both sides:
5x = 3x + 20
Take away 3x from both sides
2x = 20
Divide by 2:
X = 10
This means that (5x - 17) = (3x + 3) = 33
Since all angles must add to 360, the top angle = (360- (33*2)) /2
(360-66) /2
294 /2
147
This shows that 9x - 19y = 147
90 - 19y = 147
Minus 90 both sides
19y = 57
Y = 3
So, x = 10 and y = 3
I’m not sure try using fraction calculator it helps me a lot I’m sorry I didn’t help
