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3 years ago

Judith drove h hours at a rate of 55 mi/h. She did not reach her goal of driving 385 miles for the day. How long did she drive?

Mathematics

1 answer:

ki77a [65]3 years ago

4 0

Answer:

Judith drove h<7

Step-by-step explanation:

The first thing you would want to do is write your problem out like this 55h<385.Second thing would be to divide by 55 from both sides and that's how you get h<7.

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arc GT = 18 degrees, arc TA =32 degrees, arc NA =112 degrees, arc IN = 74 degrees. find measure of angle GET

Svet_ta [14]

Answer:

Step-by-step explanation:

7 0

2 years ago

If f(y) = 2y - 2/5,<br> what is f(f^-1(1024))?

SCORPION-xisa [38]

Answer:

-0.399

Step-by-step explanation:

f^-1(1024)=(2*1024-2/5)^-1= 0.000488

f(0.000488)=2*0.000488-2/5= -0.399

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3 years ago

Write an explicit formula for an,the Nth term of the sequence 4,12,36

Rudik [331]

Answer:

$3^{n}+3^{n-1}$

Step-by-step explanation:

Since the sequence is geometric (it multiplies the previous number each time). The nth term sequence would be $x^n + yn$

Because the sequence multiplies by 3 each time, The base number in that equation would be $3^n +yn$ .

So $3^n$ of the equation would be:
$3, 9, 27$ .

Compare the 2 equations:
4, 12, 36

3, 9 ,27

The difference between the 2 equations is: 1, 3, 9 which itself is a geometric sequence so the nth term of this new equation is: $3^{n-1}$ .

Combine these 2 equations together and you get:

$3^{n}+3^{n-1}$ .

6 0

2 years ago

In this problem we consider an equation in differential form Mdx+Ndy=0. (4x+2y)dx+(2x+8y)dy=0 Find My= 2 Nx= 2 If the problem is

zheka24 [161]

Answer:

$f(x,y)=2x^2+4y^2+2xy=C_1\\\\Where\\\\y(x)=\frac{1}{4} (-x\pm \sqrt{-7x^2+C_1} )$

Step-by-step explanation:

Let:

$M(x,y)=4x+2y\\\\and\\\\N(x,y)=2x+8y$

This is and exact equation, because:

$\frac{\partial M(x,y)}{\partial y} =2=\frac{\partial N}{\partial x}$

So, define f(x,y) such that:

$\frac{\partial f(x,y)}{\partial x} =M(x,y)\\\\and\\\\\frac{\partial f(x,y)}{\partial y} =N(x,y)$

The solution will be given by:

$f(x,y)=C_1$

Where C1 is an arbitrary constant

Integrate $\frac{\partial f(x,y)}{\partial x}$ with respect to x in order to find f(x,y):

$f(x,y)=\int\ {4x+2y} \, dx =2x^2+2xy+g(y)$

Where g(y) is an arbitrary function of y.

Differentiate f(x,y) with respect to y in order to find g(y):

$\frac{\partial f(x,y)}{\partial y} =2x+\frac{d g(y)}{dy}$

Substitute into $\frac{\partial f(x,y)}{\partial y} =N(x,y)$

$2x+\frac{dg(y)}{dy} =2x+8y\\\\Solve\hspace{3}for\hspace{3}\frac{dg(y)}{dy}\\\\\frac{dg(y)}{dy}=8y$

Integrate $\frac{dg(y)}{dy}$ with respect to y:

$g(y)=\int\ {8y} \, dy =4y^2$

Substitute g(y) into f(x,y):

$f(x,y)=2x^2+4y^2+2xy$

The solution is f(x,y)=C1

$f(x,y)=2x^2+4y^2+2xy=C_1$

Solving y using quadratic formula:

$y(x)=\frac{1}{4} (-x\pm \sqrt{-7x^2+C_1} )$

4 0

3 years ago

Who knows the answer for this question

Vadim26 [7]

Answer: 7

Work: So, the goal is to get z alone, so we are going to add 85 on both sides, cancelling on the side it's currently on. So, the new equation is going to be 25z = 175. Then, to get z even more lonely, we are going to divide 25 on both sides, and again cancelling it on the side it's currently on. So, the answer is z = 7. I hope this helps, and Happy Holidays! :)

8 0

3 years ago

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