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vovikov84 [41]
3 years ago
5

Plz help me i have 12 mins left i beg you

Mathematics
1 answer:
hram777 [196]3 years ago
4 0

Answer:

x= 70 degrees

y= 30 degrees

z= 20 degrees

Step-by-step explanation:

Angle x will be supplementary to the 110 degree angle adjacent to it since it will form a straight line. 180 - 110 = 70 degrees.

Since we know the other two angle measures in the triangle that angle y is in, we can do 180 - (110 + 40) to find angle y. 180 - 150 = 30 degrees

We also know the other 2 angle measures of the triangle that angle z is in. We can find angle z by doing 180 - (70 + 90). 180 - 160 = 20

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Answer:

egn= 7x=y

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y= days

atq...x= 3

4 0
2 years ago
Pls help me I don’t know I just need 5 and 6 to be answered
Vlada [557]

Answer:

5. Mark had 6 laps and John has 42 laps. So you could do a sentence like: John has 42 laps and Mark has 6 laps. What is the diffrence between the two laps?

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Step-by-step explanation:

6 0
2 years ago
Name the property of real numbers illustrated by the equation 16(3t + 4v) = 48t + 64v.
scZoUnD [109]
The property of real numbers illustrated by the equation 16(3t+4v)=48t+ 64v.

 Therefore, the answer is: Distributive property.

 As you can see, you have the equation 16(3t+4v), and when you apply the Distributive property, you obtain:

 16(3t+4v)
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6 0
3 years ago
7a - 17 = 9a + 1 (Finding Common Denominators)
MA_775_DIABLO [31]
<span>Answer:
3a−17=<span>1
</span></span>
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8 0
2 years ago
Suppose a certain airline uses passenger seats that are 16.2 inches wide. Assume that adult men have hip breadths that are norma
Pachacha [2.7K]

Answer:

Each adult male has a 5.05% probability of having a hip width greater than 16.2 inches.

There is a 0.01% probability that the 110 adult men will have an average hip width greater than 16.2 inches.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.

In this problem

Assume that adult men have hip breadths that are normally distributed with a mean of 14.4 inches and a standard deviation of 1.1 inches. This means that \mu = 14.4, \sigma = 1.1.

What is the probability that any one of those adult male will have a hip width greater than 16.2 inches?

For each one of these adult males, the probability that they have a hip width greater than 16.2 inches is 1 subtracted by the pvalue of Z when X = 16.2. So:

Z = \frac{X - \mu}{\sigma}

Z = \frac{16.2 - 14.4}{1.1}

Z = 1.64

Z = 1.64 has a pvalue of 0.9495.

This means that each male has a 1-0.9495 = 0.0505 = 5.05% probability of having a hip width greater than 16.2 inches.

For the average of the sample

What is the probability that the 110 adult men will have an average hip width greater than 16.2 inches?

Now, we need to find the standard deviation of the sample before using the zscore formula. That is:

s = \frac{\sigma}{\sqrt{110}} = 0.1.

Now

Z = \frac{X - \mu}{\sigma}

Z = \frac{16.2 - 14.4}{0.1}

Z = 18

Z = 18 has a pvalue of 0.9999.

This means that there is a 1-0.9999 = 0.0001 = 0.01% probability that the 110 adult men will have an average hip width greater than 16.2 inches.

7 0
3 years ago
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