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4 years ago

Plz help me i have 12 mins left i beg you

Mathematics

1 answer:

hram777 [196]4 years ago

4 0

Answer:

x= 70 degrees

y= 30 degrees

z= 20 degrees

Step-by-step explanation:

Angle x will be supplementary to the 110 degree angle adjacent to it since it will form a straight line. 180 - 110 = 70 degrees.

Since we know the other two angle measures in the triangle that angle y is in, we can do 180 - (110 + 40) to find angle y. 180 - 150 = 30 degrees

We also know the other 2 angle measures of the triangle that angle z is in. We can find angle z by doing 180 - (70 + 90). 180 - 160 = 20

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3 plus 27 divided (4 plus 5) 1/3 plus 2/5

Iteru [2.4K]

Answer:

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3 years ago

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Evaluate this expression for x =4<br><br> 4*(x-2)^2-9

TiliK225 [7]

Answer:

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Step-by-step explanation:

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8 0

3 years ago

PLZ NEED HELP Reduce this algebraic fraction.36x^5 y^8 z^10/15x^5 y^7 z^2

kvasek [131]

36/15 = 12/5
x^5 / x^5 = 1
y^8 / y^7 = y
z^10 / z^2 = z^8

Answer is 12yz^8/5

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3 years ago

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[Q71 Suppose that the height, in inches, of a 25-year-old man is a normal random variable with parameters g = 71 inch and 02 = 6

viktelen [127]

Answer: (a) Percentage of 25 year old men that are above 6 feet 2 inches is 11.5%.

(b) Percentage of 25 year old men in the 6 footer club that are above 6 feet 5 inches are 2.4%.

Step-by-step explanation:

Given that,

Height (in inches) of a 25 year old man is a normal random variable with mean $g=71$ and variance $o^{2} =6.25$ .

To find: (a) What percentage of 25 year old men are 6 feet, 2 inches tall

(b) What percentage of 25 year old men in the 6 footer club are over 6 feet. 5 inches.

Now,

(a) To calculate the percentage of men, we have to calculate the probability

P[Height of a 25 year old man is over 6 feet 2 inches]= P[X> $74in$ ]

P[X>74] = P[ $\frac{X-g}{o}$ > $\frac{74-71}{2.5}$ ]

= P[Z > 1.2]

= 1 - P[Z ≤ 1.2]

= 1 - Ф (1.2)

= 1 - 0.8849

= 0.1151

Thus, percentage of 25 year old men that are above 6 feet 2 inches is 11.5%.

(b) P[Height of 25 year old man is above 6 feet 5 inches gives that he is above 6 feet] = P[X, $6ft$ $5in$ - X, $6ft$ ]

P[X > $6ft$ $5in$ I X > $6ft$ ] = P[X > 77 I X > 72]

= $\frac{P[X > 77]}{P[ X > 72]}$

= $\frac{P[\frac{X - g}{o}>\frac{77-71}{2.5}] }{P[\frac{X-g}{o} >\frac{72-71}{2.5}] }$

= $\frac{P[Z >2.4]}{P[Z>0.4]}$

= $\frac{1-P[Z\leq2.4] }{1-P[Z\leq0.4] }$

= $\frac{1-0.9918}{1-0.6554}$

= $\frac{0.0082}{0.3446}$

= 0.024

Thus, Percentage of 25 year old men in the 6 footer club that are above 6 feet 5 inches are 2.4%.

4 0

4 years ago

HELP ASAP!!! Alex bought a notebook containing 96 pages, and numbered them from 1 through 192. Bob tore out 25 pages of Alex’s n

zubka84 [21]

<h3>Answer: No it is not possible</h3>

=====================================================

Explanation:

Page 1 is labeled with 1 and 2, which sum to 1+2 = 3

Page 2 is labeled with 3 and 4 which sum to 3+4 = 7

Page 3 is labeled with 5 and 6 which sum to 5+6 = 11

and so on until we reach

Page 96 is labeled with 191 and 192, which sum to 191+192 = 383

Note how each page has an odd page number label and an even number label (odd on the front side; even on the back side). Adding any odd number to an even number will result in an odd number. We can prove it as such

x = some odd number = 2m+1, m is any integer

y = some even number = 2n, n is an integer

x+y = 2m+1+2n = 2(m+n)+1 = some other odd integer because it is in the form 2p+1 with p = m+n as an integer

This explains why the results 3,7,11,..,383 are all odd.

------------------------

So we effectively have this set of values {3,7,11,...,383}. This is an arithmetic sequence with 3 as the first term and 4 as the common difference.

If we add two odd numbers together, we get an even number (proof is similar to one shown above)

odd + odd = even

But if we add in another odd number, then we'll go back to an odd result

odd + odd + odd = odd

If we have an odd number of odd numbers added up, then the result will be odd. In this case, we're adding 25 values from the set {3,7,11,...,383}. The value 25 is odd, so we have an odd number of values from {3,7,11,...,383} being added up. Therefore, the result Bob will get will always be odd. There is no way to get a sum of 2012 because this value is even.

3 0

3 years ago