3 years ago

Which of the following are solutions to 2x^2 -8x -90

1 answer:

6 0

Please equate 2x^2 -8x -90 to zero: 2x^2 -8x -90=0

Next, reduce 2x^2 -8x -90=0 by div. all terms by 2: x^2 -4x -45=0

Next, factor the poly: (x-9)(x+5) = 0

Set each factor = to 0 and solve for x:

x-9=0 => x=9
x+5=0 => x= -5

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Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.

prohojiy [21]

Answer:

$2.25$

Step-by-step explanation:

$(6x^{-2})^2(0.5x)^4\\\\=(6^2(x^{-2})^{2})(0.5^4x^4)\ \ \ \ \ \ \ \ \ \ \ \ \ as\ (ab)^m=a^mb^m\\\\=36\times 0.5^4((x^{-2})^2x^4)\ \ \ \ \ \ \ \ \ \ as\ multiplication\ is\ associative\ a(bc)=(ab)c\\\\=36\times 0.0625(x^{-4}x^4)\ \ \ \ \ \ \ \ \ \ \ as\ (x^m)^n=x^{mn}\\\\=(36\times 0.0625)(x^{-4+4})\ \ \ \ \ \ \ \ \ \ \ as\ x^mx^n=x^{m+n}\\\\=2.25x^0\\\\=2.25\ \ \ \ \ \ \ \ \ \ \ \ as\ x^0=1\\\\(6x^{-2})^2(0.5x)^4=2.25$

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