Someone plss help plss helppp plllsss Will mark brainliestSomeone plss help plss helppp plllsss Will mark brainliestSomeone plss
help plss helppp plllsss Will mark brainliestSomeone plss help plss helppp plllsss Will mark brainliestSomeone plss help plss helppp plllsss Will mark brainliestSomeone plss help plss helppp plllsss Will mark brainliest
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The figure below shows a diagram of this problem. First of all we graph the hemisphere. This one has a radius equal to 1. Given that z ≤ 0 a sphere will be valid only in the negative z-axis, that is, we will get a half of a sphere that is the hemisphere shown in the figure. We know that this hemisphere is oriented by the inward normal pointing to the origin, then we have a Differential Surface Vector called N, using the Right-hand rule <span>the boundary orientation is </span>counterclockwise.
Therefore, the answer above False
Therefore, the answer above False