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Fofino [41]
3 years ago
12

Someone plss help plss helppp plllsss Will mark brainliestSomeone plss help plss helppp plllsss Will mark brainliestSomeone plss

help plss helppp plllsss Will mark brainliestSomeone plss help plss helppp plllsss Will mark brainliestSomeone plss help plss helppp plllsss Will mark brainliestSomeone plss help plss helppp plllsss Will mark brainliest

Mathematics
1 answer:
Vladimir [108]3 years ago
4 0

Answer:

( 4,4 )

Step-by-step explanation:

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58-(1/4)2 i dont get how to solve this
xeze [42]

Answer:

57.5

Step-by-step explanation:

First you would have to multiply following PEMDAS so

(1/4)(2)

=0.5

Then subtract 58 and 0.5

58-0.5

=57.5

and thats your answer

5 0
3 years ago
Read 2 more answers
The sum of two numbers is 53. If twice the 1st number minus 3 times the second number is 26, find both numbers.
zhannawk [14.2K]
F twice the 1st number minus 3 times the second number is 26<span>, </span>find both<span> ... </span>Twice the first number<span> is eleven more than </span>the sum<span> of the other </span>two numbers<span>.</span>
3 0
3 years ago
Please show work and thank youuu
Assoli18 [71]

Answer:  6\sqrt{3}

======================================================

Explanation:

Method 1

We can use the pythagorean theorem to find x.

a^2+b^2 = c^2\\\\6^2+x^2 = 12^2\\\\36+x^2 = 144\\\\x^2 = 144-36\\\\x^2 = 108\\\\x = \sqrt{108}\\\\x = \sqrt{36*3}\\\\x = \sqrt{36}*\sqrt{3}\\\\x = 6\sqrt{3}\\\\

-----------------------------------

Method 2

Use the sine ratio to find x. You'll need a reference sheet or the unit circle, or simply memorize that sin(60) = sqrt(3)/2

\sin(\text{angle}) = \frac{\text{opposite}}{\text{hypotenuse}}\\\\\sin(60^{\circ}) = \frac{x}{12}\\\\\frac{\sqrt{3}}{2} = \frac{x}{12}\\\\x = 12*\frac{\sqrt{3}}{2}\\\\x = 6\sqrt{3}\\\\

-----------------------------------

Method 3

Similar to the previous method, but we'll use tangent this time.

Use a reference sheet, unit circle, or memorize that tan(60) = sqrt(3)

\tan(\text{angle}) = \frac{\text{opposite}}{\text{adjacent}}\\\\\tan(60^{\circ}) = \frac{x}{6}\\\\\sqrt{3} = \frac{x}{6}\\\\x = 6\sqrt{3}\\\\

-----------------------------------

Method 4

This is a 30-60-90 triangle. In other words, the angles are 30 degrees, 60 degrees, and 90 degrees.

Because of this special type of triangle, we know that the long leg is exactly sqrt(3) times that of the short leg.

\text{long leg} = (\text{short leg})*\sqrt{3}\\\\x = 6\sqrt{3}\\\\

The short leg is always opposite the smallest angle (30 degrees).

3 0
2 years ago
An election campaign organizer bought 20,000 buttons to hand out for her candidate. The organizer handed out 14,000 of the butto
notsponge [240]

Answer:

help me

Step-by-step explanation:

3 0
3 years ago
Give the property that justifies each step.
hjlf

Answer:

Please check the explanation below.

Step-by-step explanation:

Some of the properties are defined as:

  • <em>Distributive property</em>

a(b+c) = ab+ac

For example,

suppose a=1, b=2, c=3

1(2+3) = 1(2) + 1(3)

5 = 2+3 = 5

  • <em>Subtraction property of Equality</em>

if (a=b), then a-c = b-c

For example,

suppose a=1, b=1, c=3

if a = b ⇒ 1 = 1

then a-c = b-c ⇒ 1-3 = 1 - 3  ⇒ -2 = -2

  • <em>Addition property of Equality</em>

if (a=b), then a+c = b+c

For example,

suppose a=1, b=1, c=3

if a = b ⇒ 1 = 1

then a+c = b+c ⇒ 1+3 = 1+3  ⇒ 4 = 4

  • <em>Multiplicative property of Equality</em>

if (a=b), then a×c = b×c

For example,

suppose a=1, b=1, c=3

if a = b ⇒ 1 = 1

then a×c = b×c ⇒ 1×3 = 1 × 3  ⇒ 3 = 3

  • <em>Division property of Equality</em>

if (a=b), then a÷c = b÷c

For example,

suppose a=1, b=1, c=3

if a = b ⇒ 1 = 1

then a÷c = b÷c ⇒ 1÷3 = 1 ÷ 3  ⇒ 1/3 = 1/3

Let's solve the given equation using the above properties.

5(x+10) = 20        Given

5x+50 = 20          1) Distriburive property ∵ a(b+c) = ab+ac

5x = -30               2) Subtraction property of Equality ∵ if (a=b), then a-c = b-c

x = -6                    3) Division property of Equality  ∵ if (a=b), then a÷c = b÷c

         

5 0
3 years ago
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