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skelet666 [1.2K]
4 years ago
5

What is the second step to prove that Sn=>2+2^2+2^3+...+2^n=2(2^n-1)?

Mathematics
1 answer:
EleoNora [17]4 years ago
8 0

Answer:

Assume that Sn is valid for n = k and prove that Sn is valid for n = k + 1.

Step-by-step explanation:

This is the second step in the principal of mathematical induction. The three steps in the principals of mathematical induction are:

1. show that something works for the first case (base or anchor step)

2. assume that it works for any particular step (inductive hypothesis), and then

3. show that it works for the next case (inductive step)

p. 621 in textbook

It's weird that they put steps 2 & 3 together, but it was correct on the test so ¯\_(ツ)_/¯

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erastova [34]

Answer:

$61

Step-by-step explanation:

Given

Number of days, x = 5

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Required

Determine the expenditure per day (E'(x))

From the question, we have that

E'(x) = 10x + 11

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4 years ago
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3 years ago
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A circle has centre (3,0) and radius 5. The line y = 2x + k intersects the circle in two points. Find the set
lara [203]

A circle with center (3,0) and radius 5 has equation

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If we substitute y=2x+k in this equation, we have

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