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Inga [223]
3 years ago
12

What are the first five terms of the pattern with formula 3n + 4?

Mathematics
2 answers:
Marina86 [1]3 years ago
6 0
x_{n} =3n + 4 \\  x_{1} =3(1) + 4=7 \\  x_{2} =3(2) + 4=10 \\  x_{3} =3(3) + 4=13 \\  x_{4} =3(4) + 4 =16\\  x_{5} =3(5)+ 4 =19\\
Leviafan [203]3 years ago
4 0
In this equation we start by filling in the N with "1" then"2" then "3" and so on

3n+4=
3(1)+4=7
3(2)+4=10
3(3)+4=13
3(4)+4=16
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Answer:

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Natali5045456 [20]

Hi. I was unsure of what exactly you wanted from this equation, so here's a quick analysis:

<em>f(x) = 2(x - 3)^2 - 2</em>

<em></em>

Domain: (-∞, ∞)

Range: (-2, ∞)

X-intercepts: (4, 0), (2, 0)

Y-intercept: (0, 16)

Axis of Symmetry: x = 3

Minimum value (vertex): (3, -2)

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4 0
3 years ago
2/0 = 32/48 = 30/0. What number shpuld come in place of the zeros?​
Anton [14]

Answer:

\sf \dfrac{2}{3}  = \dfrac{32}{48}  = \dfrac{30}{45}

<h3><u>For the 1st part</u></h3>

\sf \rightarrow \dfrac{2}{x} = \dfrac{32}{48}

\sf \rightarrow 2(48)= {32x}

\sf \rightarrow 32x= 96

\sf \rightarrow x = 3

<h3><u>For the 2nd part</u></h3>

<u />\rightarrow \sf \dfrac{32}{48} = \dfrac{30}{y}

\rightarrow \sf {32y} = 30(48)

\rightarrow \sf {32y} = 1440

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