What is the sum of the interior angles of the pentagon
1 answer:
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A triangle solver tells you
C = 85°
b ≈ 8.4
c ≈ 10.4
From the sum of angles of a triangle,
C = 180° -42° -53° = 85°
From the law of sines
b = sin(53°)/sin(42°)*7 ≈ 8.355
c = sin(85°)/sin(42°)*7 ≈ 10.422
C = 85°
b ≈ 8.4
c ≈ 10.4
From the sum of angles of a triangle,
C = 180° -42° -53° = 85°
From the law of sines
b = sin(53°)/sin(42°)*7 ≈ 8.355
c = sin(85°)/sin(42°)*7 ≈ 10.422