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2 years ago

Increase £854 by 89% Give your answer rounded to 2 DP.

Mathematics

1 answer:

kolezko [41]2 years ago

3 0

Step-by-step explanation:

Step 1: Find the answer

$854 * (1 + 0.89) = x$

$854 * 1.89 = x$

$1614.06 = x$

Answer: $x = 1614.06$

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Find the equation of the line passing through the points (1, -2) and (-2, 7). Write the equation in slop-intercept from.

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Y=-3x+1 because in the points the equation will be y+2=-3(x-1) this converted into slope intercept form is y=-3(x-1)

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2 years ago

The length of the longer leg of a right triangle is 19ft more than five times the length of the shorter leg. the length of the h

dangina [55]

Let x represent the length of the shorter leg.

Longer leg: 5x +19
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.. x^2 +(5x +19)^2 = (5x +20)^2
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3 years ago

Find the 8th term in the sequence. 4, -24, 144, -864,...

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3 years ago

Read 2 more answers

14) write the equation to the line parallel to y=3x-5 that goes through the point (-2,-7) using any form

xeze [42]

Answer:

The equation of this line would be y = 3x - 1

Step-by-step explanation:

In order to find this equation we must first find the slope of the original line. The original slope (the coefficient of x) is 3, which means the new slope will also be 3 because parallel lines have the same slope. Now, we can use this slope along with the point in point-slope form to find the equation of the line.

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3 0

3 years ago

Statistics In the manual “How to Have a Number One the Easy Way,” it is stated that a song “must be no longer than three minutes

dimaraw [331]

Answer:

We conclude that the sample is from a population of songs with a mean greater than 210 seconds.

Step-by-step explanation:

We are given that a simple random sample of 40 current hit songs results in a mean length of 252.5 seconds.

Assume that the standard deviation of song lengths is 54.5 sec.

Let $\mu$ = population mean length of the songs

So, Null Hypothesis, $H_0$ : $\mu$ $\leq$ 210 seconds {means that the sample is from a population of songs with a mean smaller than or equal to 210 seconds}

Alternate Hypothesis, $H_A$ : $\mu$ > 210 seconds {means that the sample is from a population of songs with a mean greater than 210 seconds}

The test statistics that will be used here is One-sample z-test statistics because we know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean length of songs = 252.5 seconds

$\sigma$ = population standard deviation = 54.5 seconds

n = sample of current hit songs = 40

So, the test statistics = $\frac{252.5-210}{\frac{54.5}{\sqrt{40} } }$

= 4.932

The value of z-test statistics is 4.932.

Now, at 0.05 level of significance, the z table gives a critical value of 1.645 for the right-tailed test.

Since the value of our test statistics is more than the critical value of z as 4.932 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.

Therefore, we conclude that the sample is from a population of songs with a mean greater than 210 seconds.

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2 years ago