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inessss [21]
3 years ago
5

PLS SUPER IMPORTANT SOLVE THE BOTTON ONE

Mathematics
2 answers:
marusya05 [52]3 years ago
7 0
I teach math. The answer is 2X•( 4X+1)
Contact [7]3 years ago
4 0

Answer:

I am pretty sure the answer is... 8x^2 + 6x

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I can't figure out the slope of (-5,1) and (6, 4)​
Nuetrik [128]

Answer:

3/11

Step-by-step explanation:

5 0
2 years ago
In the relation defined by the equation y = x2, for all x > 0, y is a function of x because
Slav-nsk [51]
X cannot be a negative number
7 0
3 years ago
The Sweet Treat sells 40 lbs of gummy bears and 30 caramel apples every day. At this rate, how many lbs of gummy bears will be s
Sliva [168]

Answer:

8 pounds of gummy bears.

Step-by-step explanation:

To find this answer I did:

40/30 = 4/3

Then,

4/3 x 6 = 24/3

This simplified is 8.

To check:

8/6 x 5 = 40/30

3 0
2 years ago
Factorise completely:<br> 1. 3xy - x<br>2. 4a² - 9​
Amanda [17]

Answer:

x(3y - 1) and (2a - 3)(2a + 3)

Step-by-step explanation:

(1)

3xy - x ← factor out x from each term

= x(3y - 1)

(2)

4a² - 9 ← is a difference of squares and factors in general as

a² - b² = (a - b)(a + b) , then

4a² - 9

= (2a)² - 3²

= (2a - 3)(2a + 3)

6 0
2 years ago
A set of test scores is normally distributed with a mean of 130 and a standard deviation of 30 What score is necessary to reach
nlexa [21]

Answer:

A score of 150.25 is necessary to reach the 75th percentile.

Step-by-step explanation:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

A set of test scores is normally distributed with a mean of 130 and a standard deviation of 30.

This means that \mu = 130, \sigma = 30

What score is necessary to reach the 75th percentile?

This is X when Z has a pvalue of 0.75, so X when Z = 0.675.

Z = \frac{X - \mu}{\sigma}

0.675 = \frac{X - 130}{30}

X - 130 = 0.675*30

X = 150.25

A score of 150.25 is necessary to reach the 75th percentile.

7 0
3 years ago
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