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padilas [110]
3 years ago
13

How many solutions can be found for the linear equation 3(x/2 + 5 ) - 6 = ( 9x + 18 ) / 3

Mathematics
1 answer:
I am Lyosha [343]3 years ago
5 0

answer: it would be one solution, becasue the variables are different and  the constants dont matter, since the variables are different

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How to make -4 4_25 it to a decimal
Semenov [28]

it is 0.16 I am sorry if it is wrong
5 0
3 years ago
Please help with this Piecewise problem!!
tino4ka555 [31]

Remark

That was well worth doing. Desmos gave you the answer to the graph. Unfortunately I can only give you the correct graph. You will have to figure out from the choices which one is the correct answer -- or edit it so I can see what the rest of the question is.

Graph

The red one is f(x) is x + 3 {x <= -2}

The blue one is f(x) is x^2 - 1 {-2 <x <1} Notice the gap at 2. It is not continuous

The green one is f(x) is log_2(-x + 3)  {1 <=x < 3} and there is a gap between the blue and green one.

4 0
3 years ago
Simplify 8c- 4d + 8d +9c - 18c
neonofarm [45]

-c +4d

Step-by-step explanation:

8c - 4d + 8d + 9c - 18c

Group like terms and simplify

8c + 9c - 18c - 4d + 8d \\  - c + 4d

4 0
3 years ago
Read 2 more answers
Find an equation of the circle that satisfies the given conditions. Endpoints of a diameter are P(−2, 1) and Q(8, 9)
IrinaK [193]

Answer:

Equation of the circle   (x-3)²+(y-5)²=(6.4)²

                             x² -6x +9 +y² -10y +25 = 40.96

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given endpoints of diameter P(−2, 1) and Q(8, 9)

Centre of circle = midpoint of diameter

                   Centre = (\frac{-2+8}{2} ,\frac{1+9}{2} )

               Centre (h, k) = (3 , 5)

<u><em>Step(ii):-</em></u>

The distance of two end points

PQ = \sqrt{(x_{2}-x_{1} )^{2} +(y_{2} -y_{1} )^{2}  }

PQ= \sqrt{(8+2 )^{2} +(8 )^{2}  }

PQ = √164 = 12.8

Diameter    d = 2r

                 radius r = d/2

                Radius r = 6.4

<u><em>Final answer:-</em></u>

Equation of the circle  

                    (x-h)²+(y-k)² = r²

                   (x-3)²+(y-5)²=(6.4)²

x² -6x +9 +y² -10y +25 = 40.96

x² -6x  +y² -10y  = 40.96-34

x² -6x  +y² -10y -7= 0

4 0
3 years ago
Use subsititution to solve each system of equations. [x=2y] [y = x -2]
emmasim [6.3K]

Answer:

x=4

y=2

You can substitute the equations like y=1/2x and -x+y+2.

8 0
3 years ago
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