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3 years ago

How many solutions can be found for the linear equation 3(x/2 + 5 ) - 6 = ( 9x + 18 ) / 3

1 answer:

5 0

answer: it would be one solution, becasue the variables are different and the constants dont matter, since the variables are different

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34.231+45.23 somebody plz help me!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

olga2289 [7]

The answer is 79.461

6 0

3 years ago

Suppose the value R(d) of d dollars in euros is given by R(d)-d The cost P(n) in dollars to purchase and ship n purses is given

S_A_V [24]

<u>Corrected Question</u>

Suppose the value R(d) of d dollars in euros is given by $R(d)=\dfrac67 d$ . The cost in dollars to purchase and ship n purses is given by P(n)=66n+23. Write a formula for the cost, Q(n) in euros to purchase and ship n purses.

Answer:

$Q(n)=\dfrac67(66n+23)$

Step-by-step explanation:

The value R(d) of d dollars in euros is given by $R(d)=\dfrac67 d$

Therefore:

$R(1)=\dfrac67$

$T$hat is, 1 dollars =\dfrac67$ euros$

The cost P(n) in dollars to purchase and ship n purses is given by:

$P(n) = 66n+23.$

Therefore, the cost, Q(n) in euros to purchase and ship n purses

$=\dfrac67 \cdot P(n)\\Q(n)=\dfrac67(66n+23)$

8 0

3 years ago

I need help with 18-19

Svet_ta [14]

Answer:

18-19= -1

Step-by-step explanation:

18-19=-1

Sweetheart, you cant subtract a smaller number from an bigger number or it will be a negitive number so the answer is -1

8 0

2 years ago

Read 2 more answers

Nancy had 16 chocolate candies in a bag. Her mother put a handful of candies in the bag. When Nancy counts her chocolate candies

Reika [66]

Answer:

she had 16

She got c

16 + c

She now has 32

16 + c = 32

I don't know if that's the exact answer, but basically, 16 needs to be added to c, and it needs to equal 32.

Hope this helps! :)

8 0

3 years ago

Read 2 more answers

The equation v(x)=32500(0.92)^x how much more is the truck worth after two years than after three years

Lyrx [107]

Answer:

the difference: $2,192.64

Step-by-step explanation:

After 1 year, the truck has lost 8% of its value: v(x) = $32,500(0.92)^1, or

$29,900.

After 2 years, v(x) = $32,500(0.92)^2, or $27,500. Finally, after 3 years,

v(x) = $32,500(0.92)^3 = $25,307.36.

Subtracting $25,307.36 (the value after 3 years) from $27,500 (the value after 2 years) yields the difference: $2,192.64

6 0

3 years ago