The following statements in this case are correct:
1) The independent variable is t.
2) The dependent variable is f (t).
3) When f (2) = 1,323, the 2 represents "the year 2002," and the 1,323 represents "1,323 tons of garbage produced."
4) When f (4) = 1,458.6, the 4 represents "the year 2004," and the 1,458.6 represents "1,458.6 tons of garbage produced."
Note: for statements 3) and 4) the following is done:
f (2) = (1200) * (1.05) ^ 2 = 1323
f (4) = (1200) * (1.05) ^ 4 = 1458.6
The difference between 1,968 and 3,000 is 1,038. You can check the answer using inverse operations by adding 1,038 and 1,968. If it gives 3,000 then the answer is right. 3, 000 - 1,968 = 1,038.
1,038 + 1,968 = 3,000
1)
Perimeter of figure = 2×(L+b) + πr
=> Perimeter of figure = 2×(18+14) +3.14×7
=> Perimeter of figure = 2×32 + 21.98
=> Perimeter of figure = 64 + 21.98
=> Perimeter of figure = 85.98 cm <em><u>Ans.</u></em>
2)
Perimeter of figure = πrl + πr
=> Perimeter of figure = 3.14×3.5×4 + 3.14×3.5
=> Perimeter of figure = 43.96 + 10.99
=> Perimeter of figure = 54.95 cm <em><u>A</u></em><em><u>ns.</u></em>
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A
The velocity is found by differentiating the given cubic.
x'(t) = 2t^3 - 15t^2 + 24t This is the distance
x'(t) = 6t^2 - 20t + 24 This is the velocity (first derivative)
x"(t) = 12t - 20 This is the acceleration (second derivative)
x'(2) = 6(2)^2 - 20*2 + 24
x'(2) = 24 - 40 + 24
x'(2) = 48 - 40
x'(2) = 8 units per second.
x"(2) = 12(2) - 20
x"(2) = 24 - 20
x"(2) = 4 units per second^2
B
at t = 2 the acceleration is positive. That's a pretty good indication that the velocity is increasing.
C
When x(t) is minus, then the particle is moving left.
At t = 0 the object is not moving (x(t) = 0)
Any value less than 0 and the object is moving left. Try a couple of values.
x(-1) = 2(-1)^3 - 15(-1)^2 +24(-1) Whatever that is is minus.
t < 0 will make the object move left.
Answer:
mean=28.8
median=31
Step-by-step explanation:
mean=sum of all values/number of all values
mean=40+45+7+21+31+40+45+7+21+31/10
=288/10
mean=28.8
Median
arrrange in order
7,7,21,21,31,31,40,40,45,45
in case of even ungrouped data median is the average of middle two values
= (31+31)/2
median =31