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Eva8 [605]
2 years ago
5

20 POINTS - Can someone answer this pls

Mathematics
1 answer:
Temka [501]2 years ago
5 0

Answer:

Step-by-step explanation:

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Please answer this this question is a motion problem:
mr_godi [17]
T1 + t2 = 2h and 30min;
t1 * 600 = t2 * 400 => t2 = (3/2) * t1;

then, t1 +  (3/2) * t1 = 2h and 30min => 2t1 + 3t1 = 5h => 5*t1 = 5h => t1 = 1h => t2 = 1h and 30 min;

The distance is 2 * 1 * 600 = 1200miles;
7 0
3 years ago
How to solve 6x+25=10x-47
Irina-Kira [14]

Answer:

Step-by-step explanation:

6x+25=10x-47

16x -22

(6x + 10x) + (-47 +25)

8 0
3 years ago
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When ms. shreve solved an equation in class, she checked her solution and found that it did not make the equation true! Examine
IgorC [24]
The first part of the second line, she left the -5 there. The correct work and solution should be this:
5(2x-1)-3x=5x+9
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</span></span>2x-5=9
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7 0
3 years ago
Is the statement true or false?<br> 4-2(3+7 =4 - 2 • 3 + 2 • 7
Vesnalui [34]
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6 0
2 years ago
∆ABC is reflected about the line y = -x to give ∆A'B'C' with vertices A'(-1, 1), B'(-2, -1), C(-1, 0). What are the vertices of
blsea [12.9K]
Hi there!
Reflections across the line y = -x always go by the rule (-y, -x). We can use this rule to get our answer here. We are given the aftermath of the reflection coordinates, which are <span>A'(-1, 1), B'(-2, -1), and C'(-1, 0). All we have to do now is switch up the coordinate values and multiply them by -1. Here is the work - 
A'(-1, 1) => (1, -1) => x -1 => A(-1, 1)
B'(-2, -1) => (-1, -2) => x -1 => B(1, 2)
C'(-1, 0) => (0, -1) => x -1 => C(0, 1)
Therefore, the coordinates of Triangle ABC are A(-1, 1); B(1, 2); C(0,1). Hope this helped and have a phenomenal day!</span>
6 0
3 years ago
Read 2 more answers
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