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Snowcat [4.5K]
3 years ago
12

(35/47)^0 worth 10 points

Mathematics
1 answer:
marusya05 [52]3 years ago
4 0
<h3>Answer:  1</h3>

=================================================

Explanation:

The rule is

x^0 = 1

where x is nonzero (ie, not equal to zero). So whatever number you raise to the zeroth power, the answer is always 1.

---------------

Let's see why this rule works

x^1 = x   ... raising something to the first power is itself

(x^1)/x = x/x ... divide both sides by x

(x^1)/x = 1 .... turn the 'x/x' into 1

(x^1)/(x^1) = 1 .... rewrite the second 'x' as 'x^1'

x^(1-1) = 1 ... subtract exponents

x^0 = 1

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Step-by-step explanation:

The numerical expression for the cost of 1 dozen eggs is 33.75/15.

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4 years ago
What is the probability of these events when we randomly select a permutation of {1,2, ..., n} where n≥4? a) 1 precedes 2 c) 1 i
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Answer:

a) 1/2

b) 1/n

c) 1/4

Step-by-step explanation:

a) For each permutation, either 1 precedes 2 or 2 precedes 1. For each permutation in which 1 precedes 2, we can swap 1 and 2 to obtain a permutation in which 2 preceds 1. Thus, half of the total permutations will involve in 1 preceding 2, hence, the probability for a permutation having 1 before 2 is 1/2.

c) If 2 is at the start of the permutation, then it is impossible for 1 to be before 2. If that is not the case, then 1 has a probability of 1/n-1 to be exactly in the position before 2. We can divide in 2 cases using the theorem of total probability,

P( 1 immediately preceds 2) = P (1 immediately precedes 2 | 2 is at position 1) * P(2 is at position 1) + P(1 immediately precedes 2 | 2 is not at position 1) * P(2 is not at position 1) = 0 * 1/n + (1/n-1)*(n-1/n) = 1/n.

d) We can divide the total of permutations in 4 different groups with equal cardinality:

  • Those in which n precedes 1 and n-1 precedes 2
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  • those in which 1 precedes n and n-1 precedes 2
  • those in which 1 precedes n and 2 precedes n-1

All this groups have equal cardinality because we can obtain any element from one group from another by making a permutations between 1 and n and/or 2 and n-1.

This means that the total amount of favourable cases (elements of the first group) are a quarter of the total, hence, the probability of the event is 1/4.

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3 years ago
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Answer:

54

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Answer:

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Step-by-step explanation:

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Since it is a fraction, it is NOT irrational (which means "not rational" or "not a fraction).

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