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4 years ago

Which is an exponential growth function?

1 answer:

5 0

Answer: Exponential growth is a pattern of data that shows greater increases with passing time, creating the curve of an exponential function.

Step-by-step explanation:

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sam has to climb to the top of the building for his firefighter training. he doesn’t know how high it is. he is 6ft y’all and hi

Virty [35]

The height of building is 35 feet

Solution:

Given that,

Sam is 6 feet tall and his shadow is 3.6 feet tall

The shadow of building is 21 feet long

To find: height of building

We can solve this by setting up a ratio comparing the height of the building to the height of the Sam and shadow of the building to the shadow of the Sam

Let us consider,

$h_b$ = height of building

$h_m$ = height of Sam

$s_b$ = shadow of building

$s_m$ = shadow of Sam

Therefore,

$\frac{\text {height of building}}{\text {shadow of building}}=\frac{\text {height of Sam}}{\text {shadow of Sam}}$

$\frac{h_{b}}{S_{b}}=\frac{h_{m}}{S_{m}}$

Substitute the values,

$\begin{aligned}&\frac{h_{b}}{21}=\frac{6}{3.6}\\\\&h_{b}=\frac{6}{3.6} \times 21\\\\&h_{b}=35\end{aligned}$

Thus height of building is 35 feet

5 0

3 years ago

Simplify the expression below: 12x - 13 - x -9 + 10x

sdas [7]

Answer:

21x-22

Step-by-step explanation:

Try using m a t h w a y if you need help with any other questions

5 0

3 years ago

Which value, when placed in the box, would result in a system of equations with infinitly many solutions? Y=2x - 5 2y-4x=

Nezavi [6.7K]

Given:

The system of equations is

$y=2x-5$

$2y-4x=?$

To find:

The missing value for which the given system of equations have infinitely many solutions.

Solution:

Let the missing value be k.

We have,

$y=2x-5$

$2y-4x=k$

Taking all the terms on the left side, the given equations can be rewritten as

$-2x+y+5=0$

$-4x+2y-k=0$

The system of equations $a_1x+b_1y+c_1=0$ and $a_2x+b_2y+c_2=0$ have infinitely many solutions if

$\dfrac{a_1}{a_2}=\dfrac{b_1}{b_2}=\dfrac{c_1}{c_2}$

We have,

$a_1=-2,b_1=1,c_1=5$

$a_2=-4,b_2=2,c_2=-k$

Now,

$\dfrac{-2}{-4}=\dfrac{1}{2}=\dfrac{5}{-k}$

$\dfrac{1}{2}=\dfrac{1}{2}=\dfrac{5}{-k}$

$\dfrac{1}{2}=\dfrac{5}{-k}$

On cross multiplication, we get

$-k=10$

$k=-10$

Therefore, the missing value is -10.

6 0

3 years ago

Rewrite the expression by using grouping symbols

Elan Coil [88]

Answer:

D) $y(5+a)$

Step-by-step explanation:

Given expression:

$y\times5+y\times a$

The above expression can be rewritten using grouping symbols by using properties of equality.

We apply distributive property of multiplication according to which:

$ab+cb=b(a+c)$

the product of a number and each addend individually added together is equal to the product of that number and sum of the addends.

So, we can write

$y\times5+y\times a=y(5+a)$

5 0

3 years ago

PLZZ HELP!!!!!!!!!!!!

Goshia [24]

5.5
8
30
31
42
24
8
Hope this helps:)

3 0

3 years ago

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