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sveta [45]
3 years ago
14

Find a counterexample for the conjecture: If n is a real number, then -n is a negative

Mathematics
1 answer:
kiruha [24]3 years ago
6 0

Answer:

Step-by-step explanation:

-5 is a real number, right ?

- (-5) = 5 is not negative

thanks

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What is 9 7/12 + 4 3/4​
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Answer:

14 1/3

Step-by-step explanation:

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3 years ago
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In the last chapter, we looked at three outliers arising from a plot of Average Wind Speed by Month in the Hopkins Forest. Each
Aloiza [94]

Answer:

Step-by-step explanation:

Hello!

We have the information of the average wind speed for three months:

February:

Mean: 2.324

SD: 1.577

Otlier: 6.73 mph

June:

Mean: 0.857

SD: 0.795

Otlier: 3.93 mph

August

Mean: 0.63

SD: 0.597

Outlier: 2.53mph

a)

Z=  X - μ ~N(0;1)

δ

Z_{February}= \frac{6.73 - 2.324}{1.577}

Z_{Februar}= 2.793 ≅2.79

Z_{June}= \frac{3.93 - 0.857 }{0.795}

Z_{June}= 3.87

Z_{August}= \frac{2.53 - 0.63}{0.597}

Z_{Augus}= 3.182 ≅ 3.18

b)

Comparing the three Z-scores you can say that the strongest wind event was in June. The number obtained means that is the furthest one in relation to the mean.

4 0
4 years ago
Ticket sales. stacey is selling tickets to the school play. the tickets are $8 for adults and $4 for children. she sells twice a
MrRissso [65]
Adult tickets + kids tickets = 120$
Y represents kids tickets
Z represents adult tickets

Z = twice kids tickets = 2Y

In ecuation:

Z + Y = 120$

Replace Z with 2Y

2Y + Y = 120 $

3Y= 120 / divided by 3

Y = 40$

You know the cost for 1 kid ticket

40 : 4 = 10 kids tickets sold

Z = 2x 40= 80$ for adult tickets

80:8 = 10 adult tickets sold
6 0
3 years ago
Determine the x-intercepts of the function. Check all
aev [14]
No one can answer this problem without a picture
7 0
4 years ago
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The altitude drawn to the hypotenuse of a right triangle divides the hypotenuse into segments such that their lengths are in rat
Zanzabum

In geometry, it would be always helpful to draw a diagram to illustrate the given problem.

This will also help to identify solutions, or discover missing information.

A figure is drawn for right triangle ABC, right-angled at B.

The altitude is drawn from the right-angled vertex B to the hypotenuse AC, dividing AC into two segments of length x and 4x.


We will be using the first two of the three metric relations of right triangles.

(1) BC^2=CD*CA (similarly, AB^2=AD*AC)

(2) BD^2=CD*DA

(3) CB*BA = BD*AC


Part (A)

From relation (2), we know that

BD^2=CD*DA

substitute values

8^2=x*(4x) => 4x^2=64, x^2=16, x=4

so CD=4, DA=4*4=16 (and AC=16+4=20)


Part (B)

Using relation (1)

AB^2=AD*AC

again, substitute values

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=>

AB

=sqrt(8^2*5)

=8sqrt(5)

=17.89 (approximately)

6 0
4 years ago
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