Answer:
14 1/3
Step-by-step explanation:
Answer:
Step-by-step explanation:
Hello!
We have the information of the average wind speed for three months:
February:
Mean: 2.324
SD: 1.577
Otlier: 6.73 mph
June:
Mean: 0.857
SD: 0.795
Otlier: 3.93 mph
August
Mean: 0.63
SD: 0.597
Outlier: 2.53mph
a)
Z= X - μ ~N(0;1)
δ

≅2.79



≅ 3.18
b)
Comparing the three Z-scores you can say that the strongest wind event was in June. The number obtained means that is the furthest one in relation to the mean.
Adult tickets + kids tickets = 120$
Y represents kids tickets
Z represents adult tickets
Z = twice kids tickets = 2Y
In ecuation:
Z + Y = 120$
Replace Z with 2Y
2Y + Y = 120 $
3Y= 120 / divided by 3
Y = 40$
You know the cost for 1 kid ticket
40 : 4 = 10 kids tickets sold
Z = 2x 40= 80$ for adult tickets
80:8 = 10 adult tickets sold
No one can answer this problem without a picture
In geometry, it would be always helpful to draw a diagram to illustrate the given problem.
This will also help to identify solutions, or discover missing information.
A figure is drawn for right triangle ABC, right-angled at B.
The altitude is drawn from the right-angled vertex B to the hypotenuse AC, dividing AC into two segments of length x and 4x.
We will be using the first two of the three metric relations of right triangles.
(1) BC^2=CD*CA (similarly, AB^2=AD*AC)
(2) BD^2=CD*DA
(3) CB*BA = BD*AC
Part (A)
From relation (2), we know that
BD^2=CD*DA
substitute values
8^2=x*(4x) => 4x^2=64, x^2=16, x=4
so CD=4, DA=4*4=16 (and AC=16+4=20)
Part (B)
Using relation (1)
AB^2=AD*AC
again, substitute values
AB^2=16*20=320=8^2*5
=>
AB
=sqrt(8^2*5)
=8sqrt(5)
=17.89 (approximately)