Oh thats easy. It's a piece of cake. Just use your calculator
Answer:
273 = 3 x 7 x 13.
273 is 100010001 in base 2 (binary), 333 in base 9, and 111 in base 16.
The 273rd prime minus the sum of gaps between the first 273 consecutive primes minus 1 equals 273.
273 is the sum of each of two consecutive sums of consecutive numbers: 273 = 36 + 37 + 38 + 39 + 40 + 41 + 42 = 43 + 44 + 45 + 46 + 47 + 48.
Answer:
R=6.57978
also everyone add my sc- amber_hughes42
Step-by-step explanation:
we are given
I=3.8 \times 10^6
I_0=1
now, we can use formula
R=log(\frac{I}{I_0} )
now, we can plug these values
we get
R=log(\frac{3.8 \times 10^6}{1} )
Answer:
a = (d-c)/b
Step-by-step explanation:
ab + c = d
ab = d -c
a = (d-c)/b
Answer:
450.19 ×10 and 7 as the index
