Answer:
The Expected Earning for the college graduates is 40,000
Explanation:
The Expected Earning for a college alum with a four year college education in financial matters is determined as weighted normal all things considered, utilizing likelihood of every result as its weight.
Although the Expected Earning is;
Expected Earning = (25% × 30,000) + (50% × 40,000) + (25% × 50,000)
Expected Earning = 0.25 × 30,000 + 0.5 × 40,000 + 0.25 × 50,000
Expected Earning = 7500 + 20,000 + 12,500
Expected Earning = 40,000
Answer:
Gas Compressor Operator
Explanation:
A gas compressor operator works with steam or internal combustion engines to compress and transmit gases through pipelines.
He or she directs various control nodes and adjust valves in the compressor engines, pumps, and other related equipment. They monitor pressure, temperature gauges, and other safety components to ensure the safe passage of gases in the pipelines.
Answer: $8.81
Explanation:
To solve this, add the present values of the dividends from years 3, 4 and 5 and then add the present value of the terminal value of the stock at year 5.
Year 3 dividend = $0.50
Year 4 dividend = 0.50 * (1 + 49%) = $0.745
Year 5 dividend = 0.745 * 1.49 = $1.11005
= Dividend in year 3 / (1 + required rate of return)³ + Dividend in year 4 / (1 + required rate of return)⁴ + Dividend in year 5 / (1 + required rate of return)⁵ + (Dividend in year 5 * (1 + growth rate) / ( required rate of return - growth rate ) ) / (1 + required rate of return)⁵
= 0.5 / 1.16³ + 0.745/1.16⁴ + 1.11005/1.16⁵ + ( 1.11005 / (16% - 9%)) / 1.16⁵
= $8.81
Answer:
The answer is below.
Explanation:
The z score is a used in statistics to determine by how many standard deviations the raw score is above or below the mean. The z score is given by:
a) Given that n = 100, μ = 2000, σ = 18
For x < 1995 millimeters:
From the normal distribution table, P(x < 1995) = P(z < -2.78) = 0.0027
b) P(z > z*) = 10% = 0.1
P(z < z*) = 1 - 0.1 = 0.9
z* = 1.28
From the normal distribution table, P(z < z
