Hey can you give the rest of the question
You need to find the first common multiple of both 7 and 8. In this case, the LCM (lowest common multiple) is actually the numbers multiplies by each other, or 56. So the answer is 56 seconds
Hope this helps
Answer:
A, B, D
Step-by-step explanation:
A) y squared times y squared you just add the exponents
B) y^6/y^2 write it out as (y)(y)(y)(y)(y)(y)/(y)(y) then u cancel out two "y" from numerator and denominator and is left with y^4
C) is just 0 so its wrong
D) is the same process as B just cancel out 5 "y" from numerator and denominator and is left with y^4
E) is incorrect bc you need to add the exponents and you will get y^5 which is not equal to y^4 so yeah its wrong
Answer:
y=(x+1)^2
Step-by-step explanation:
we have the following
the values of y are squares so we can write
so as you can see when
so our relation is
Answer:
Yes
Step-by-step explanation:
Given that In my data set of 10 exam scores, the mean turned out to be the score of the person with the third highest grade.
No two people got the same score.
Let the scores be a,b,c,d,e in ascending order where no two scores are equal
If a+b=d+e =2c then we can have c as the mean of the scores of 5 persons
This is because
Total sum = a+b+c+d+e = (a+b)+c+(d+e)
= 2c+c+2c=5c
Average= 5c/5 = c
It makes sense and there are chances as long as the above condition is satisfied.
