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2 years ago

How do i do this PLEASE HELP

Mathematics

1 answer:

Scorpion4ik [409]2 years ago

6 0

X=10
-3,-2,-1,0,1,2,3
Add 1,2,3+10
=16

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Write an inequality that represents the following. Employees receive a bonus

Reptile [31]

So Is This (80+15) or something

7 0

3 years ago

There are a total of 96 children in Years 4, 5 and 6

BaLLatris [955]

Answer: 20 children

Step-by-step explanation:

Given

Year 4: 11 cannot swim

Year 5: 21 can swim

Year 6: 18 of 30 can swim

Total 96 children

Total 37 cannot swim

First Step: find the number of people from year 5 who cannot swim

There are 30-18=12 people who cannot swim in year 6
There are 11 who cannot swim in year 4
Thus, we use the total number [37]-[year 4+year 6]=37-23=14 people who cannot swim in the year 5

Second Step: find the number of children in year 5

There are 21 children who can swim
There are 14 children who cannot swim
21+14=35 children

Third Step: find the number of children in year 4 who can swim

There are 30 children in year 6
There are 35 children in year 5
There are 11 children in year 4 who cannot swim
There are in total 96 children
96-30-35-11=20 children in year 4 who can swim

Hope this helps!! :)

Please let me know if you have any questions

7 0

3 years ago

Which expression is equivalent to StartFraction (3 m Superscript negative 1 Baseline n squared) Superscript negative 4 Baseline

koban [17]

Answer:

$3m^{10}n^{-11}$

Step-by-step explanation:

Given the expression $\frac{(3m^{-1}n^{2})^{-4} }{(2m^{-2}n)^{3} }$ , we will use laws of indices to get the equivalent expression as shown below;

According to one of the law of indices,

$\frac{a^{m} }{a^{n} } = a^{m-n} \ and\ (a^{m})^{n} = a^{mn}$

$\frac{(3m^{-1}n^{2})^{-4} }{(2m^{-2}n)^{3} }\\= \frac{3m^{4}n^{-8} }{2m^{-6}n^{3} }\\= 3m^{(4-(-6))} * n^{-8-3}\\ = 3m^{10}n^{-11}$

This gives the required expression

8 0

3 years ago

Read 2 more answers

What additional information is required

Phantasy [73]

The last option all the way to the right

7 0

3 years ago

Records indicate that x years after 2008, the average property tax on a three bedroom home in a certain community was T(x) =20x^

dem82 [27]

Answer:

a) 40 dollars

b) 480 dollars

Step-by-step explanation:

Given the average property tax on a three bedroom home in a certain community modelled by the equation T(x) =20x²+40x+600, the rate at which the property tax is increasing with respect to time in 2008 can be derived by solving for the function T'(x) at x=0

T'(x) = 2(20)x¹ + 40x° + 0

T'(x) = 40x+40

At x = 0,

T'(0) = 40(0)+40

T'(0) = 40

Hence the property tax was increasing at a rate of 40dollars with respect to the initial year (2008).

b) There are 4 years between 2008 and 2012. To know how much that the tax change between the years 2008 and 2012, we will find T(4) - T(0)

Given T(x) =20x²+40x+600

T(4) =20(4)²+40(4)+600

T(4) = 320+160+600

T(4) = 1080 dollars

Also T(0) =20(0)²+40(0)+600

T(0) = 0+0+600

T(0)= 600 dollars

T(4) - T(0) = 1080 - 600

T(4) - T(0) = 480 dollars

Hence, the tax has changed by $480 between 2008 and 2012

6 0

4 years ago