Step-by-step explanation:
We are given two Triangles and we need to prove them congruent . In ∆AOC and ∆BOD , we have
Therefore by AAS congruent condition we can say that ,
Hence Proved!
Answer:
x = sqrt(11 - y) - 2 or x = -sqrt(11 - y) - 2
Step-by-step explanation:
Solve for x:
y = -x^2 - 4 x + 7
y = -x^2 - 4 x + 7 is equivalent to -x^2 - 4 x + 7 = y:
-x^2 - 4 x + 7 = y
Multiply both sides by -1:
x^2 + 4 x - 7 = -y
Add 7 to both sides:
x^2 + 4 x = 7 - y
Add 4 to both sides:
x^2 + 4 x + 4 = 11 - y
Write the left hand side as a square:
(x + 2)^2 = 11 - y
Take the square root of both sides:
x + 2 = sqrt(11 - y) or x + 2 = -sqrt(11 - y)
Subtract 2 from both sides:
x = sqrt(11 - y) - 2 or x + 2 = -sqrt(11 - y)
Subtract 2 from both sides:
Answer: x = sqrt(11 - y) - 2 or x = -sqrt(11 - y) - 2
Distance traveled during the first 4 hours: 500 m Note that the rate here was 125 m/hr.
Distance traveled during the next four hours: 3(125 m/hr)(4 hr) = 375 m
Total distance traveled: 500 m + 375 m = 875 m
Answer: k = 4, k = -4 and k = 0.
Step-by-step explanation:
If we have y = sin(kt)
then:
y' = k*cos(kt)
y'' = -k^2*son(x).
then, if we have the relation:
y'' - y = 0
we can replace it by the things we derivated previously and get:
-k^2*sin(kt) + 16*sin(kt) = 0
we can divide by sin in both sides (for t ≠0 and k ≠0 because we can not divide by zero)
-k^2 + 16 = 0
the solutions are k = 4 and k = -4.
Now, we have another solution, but it is a trivial one that actually does not give any information, but for the diff equation:
-k^2*sin(kt) + 16*sin(kt) = 0
if we take k = 0, we have:
-0 + 0 = 0.
So the solutions are k = 4, k = -4 and k = 0.