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vampirchik [111]
4 years ago
10

I need a answer to this problem asap please help

Mathematics
1 answer:
Georgia [21]4 years ago
4 0

First factor (x square -36), the answer will be (x+6)(x-6).

Second, cancel the x .

6x/ (x+6)(x-6)

4x/(6)(-6)

4x/-36

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How would I change this to standard form. <br><img src="https://tex.z-dn.net/?f=y%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20x%20-%201"
Pie

Answer:

x - 2y = 2

Step-by-step explanation:

the equation of a line in standard form is

Ax + By = C ( A is a positive integer and A, B are integers )

given y = \frac{1}{2} x - 1

multiply through by 2 to eliminate the fraction

2y = x - 2 ( subtract 2y from both sides )

0 = x - 2y - 2 ( add 2 to both sides )

x - 2y = 2 ← in standard form


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antiseptic1488 [7]
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6 0
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Graham uses a 10 by 10 grid
frozen [14]

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He cuts off a section representing a percent of the current area so that the remaining area represents the next term in the pattern, rounded to nearest whole centimeter. The area after each cut is shown on the graph.

4 0
3 years ago
Given that p=9i+12j and q=-6i-8j. Evaluate |p-q|-{|p|-|q|}
krok68 [10]

Answer:

|p-q|-(|p|-|q|) = 20

Step-by-step explanation:

First let's find the value of 'p-q':

p - q = 9i + 12j - (-6i - 8j)\\p - q = 9i + 12j + 6i + 8j\\p - q = 15i + 20j\\

To find |p-q| (module of 'p-q'), we can use the formula:

|ai + bj| = \sqrt{a^{2}+b^{2}}

Where 'a' is the coefficient of 'i' and 'b' is the coefficient of 'j'

So we have:

|p - q| = |15i + 20j| = \sqrt{15^{2}+20^{2}} = 25

Now, we need to find the module of p and the module of q:|p| = |9i + 12j| = \sqrt{9^{2}+12^{2}} = 15

|q| = |-6i - 8j| = \sqrt{(-6)^{2}+(-8)^{2}} = 10

Then, evaluating |p-q|-{|p|-|q|}, we have:

|p-q|-(|p|-|q|) = 25 - (15 - 10) = 25 - 5 = 20

7 0
3 years ago
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