There are slips of paper that are numbered from 1 to 15 in a hat. What is the theoretical probability that a slip of paper that
2 answers:
Answer:
the theoretical probability that a slip of paper that is chosen will be an even number is 0.466
Step-by-step explanation:
if we are going to choose a slip of paper with an specific condition, the theoretical probability could be calculated as a division between the total number of posibles choices and the number of choices that satisfy an specific condition.
In this case, there 15 posibles choices because we have 15 numbered slips of papers. from these 15 slips, 7 are numbered with an even number. This even numbers are: 2, 4, 6, 8, 10, 12 and 14.
Finally the theoretical probability is:
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Hello,
Vertices are on a line parallele at ox (y=-3)
The hyperbola is horizontal.
Equation is (x-h)²/a²- (y-k)²/b²=1
Center =middle of the vertices=((-2+6)/2,-3)=(2,-3)
(h+a,k) = (6,-3)
(h-a,k)=(-2,-3)
==>k=-3 and 2h=4 ==>h=2
==>a=6-h=6-2=4 (semi-transverse axis)
Foci: (h+c,k) ,(h-c,k)
h=2 ==>c=8-2=6
c²=a²+b²==>b²=36-4²=20
Equation is:
Vertices are on a line parallele at ox (y=-3)
The hyperbola is horizontal.
Equation is (x-h)²/a²- (y-k)²/b²=1
Center =middle of the vertices=((-2+6)/2,-3)=(2,-3)
(h+a,k) = (6,-3)
(h-a,k)=(-2,-3)
==>k=-3 and 2h=4 ==>h=2
==>a=6-h=6-2=4 (semi-transverse axis)
Foci: (h+c,k) ,(h-c,k)
h=2 ==>c=8-2=6
c²=a²+b²==>b²=36-4²=20
Equation is: