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Soloha48 [4]
3 years ago
5

A used book store will trade 2 of its books for 3 of yours. If Val brings in 18 books to trade, how many books can she get from

the store?
Mathematics
2 answers:
Shalnov [3]3 years ago
5 0
You need to set it up as a fraction and make the fractions equal each other. 
2/3 (2 of their books for 3 of yours)
x/18 (x amount of their books for 18 of yours)
(2/3)=(x/18)
multiply both sides by 18 
and you get 
36/3 which reduces to 12

so your answer is 12
AleksAgata [21]3 years ago
4 0

She will get 12 books from the store



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If r and s are positive integers, is \small \frac{r}{s} an integer? (1) Every factor of s is also a factor of r. (2) Every prime
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Answer:

<em>If statement(1) holds true, it is correct that </em>\small \frac{r}{s}<em> is an integer.</em>

<em>If statement(2) holds true, it is not necessarily correct that </em>\small \frac{r}{s}<em> is an integer.</em>

<em></em>

Step-by-step explanation:

Given two positive integers r and s.

To check whether \small \frac{r}{s} is an integer:

Condition (1):

Every factor of s is also a factor of r.

r \geq s

Let us consider an example:

s = 5^2 \cdot 2\\r = 5^3 \cdot 2^2

\dfrac{r}{s} = \dfrac{5^3\cdot2^2}{5^2\cdot2} = 10

which is an integer.

Actually, in this situation s is a factor of r.

Condition 2:

Every prime factor of <em>s</em> is also a prime factor of <em>r</em>.

(But the powers of prime factors need not be equal as we are not given the conditions related to powers of prime factors.)

Let

r = 2^2\cdot 5\\s =2^4\cdot 5

\dfrac{r}{s} = \dfrac{2^3\cdot5}{2^4\cdot5} = \dfrac{1}{2}

which is not an integer.

So, the answer is:

<em>If statement(1) holds true, it is correct that </em>\small \frac{r}{s}<em> is an integer.</em>

<em>If statement(2) holds true, it is not necessarily correct that </em>\small \frac{r}{s}<em> is an integer.</em>

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