Step-by-step explanation:
I'll do 2.
Alright,Alex let say we have factored a quadratic into two binomial, for example
![(5x + 3)(6x - 4)](https://tex.z-dn.net/?f=%285x%20%2B%203%29%286x%20-%204%29)
If we set both of those equal to zero
![(5x + 3)(6x + 4) = 0](https://tex.z-dn.net/?f=%285x%20%2B%203%29%286x%20%2B%204%29%20%3D%200)
We can used the zero product property in this case to find the roots of the quadratic equation.
This means that
![if \: ab = 0 \: then \: a = 0 \: and \: b = 0](https://tex.z-dn.net/?f=if%20%20%5C%3A%20ab%20%3D%200%20%5C%3A%20then%20%5C%3A%20a%20%3D%200%20%5C%3A%20and%20%5C%3A%20b%20%3D%200)
This means we set each binomal equal to zero to find it root.
![5x + 3 = 0](https://tex.z-dn.net/?f=5x%20%2B%203%20%3D%200)
![5x = - 3](https://tex.z-dn.net/?f=5x%20%3D%20%20-%203)
![x = - \frac{3}{5}](https://tex.z-dn.net/?f=x%20%3D%20%20-%20%20%5Cfrac%7B3%7D%7B5%7D%20)
![6x + 4 = 0](https://tex.z-dn.net/?f=6x%20%2B%204%20%3D%200)
![6x = - 4](https://tex.z-dn.net/?f=6x%20%3D%20%20-%204)
![x = - \frac{2}{3}](https://tex.z-dn.net/?f=x%20%3D%20%20-%20%20%5Cfrac%7B2%7D%7B3%7D%20)
So our roots are negative 3/5 and negative 2/3 using zero product property
Answer:
Component form : (-7 , 2)
Step-by-step explanation:
P(4 , 5) = P'(4 +x , 5+y) = P'(-3 , 7)
4 + x = -3
x = -3 - 4
x = -7
5 + y = 7
y = 7 - 5
y = 2
Vector form : -7i + 2j
Component form : (-7 , 2)
Answer:
-2/3
Step-by-step explanation:
A rational number is a number that can be expressed by a fraction so when y add to fractions it’s a rational number.
Answer:
two and one fifth
Step-by-step explanation:
Answer:
Step-by-step explanation:
no