The answer is not D it would be B: You received a bonus at work

Complete the point-slope equation of the line through (2,3 and (7,4). Use exact numbers.

uysha [10]

The point-slope equation of the line is $y-3=\frac{1}{5}(x-2)$

Step-by-step explanation:

The form of the point-slope equation is $y-y_{1}=m(x-x_{1})$ , where

m is the lope of the line
$(x_{1},y_{1})$ is a point lies on the line

The slope of a line $m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$ , where

$(x_{1},y_{1})$ and $(x_{2},y_{2})$ are two points on the line

∵ The line through (2 , 3) and (7 , 4)

∴ $x_{1}$ = 2 and $x_{2}$ = 7

∴ $y_{1}$ = 3 and $y_{2}$ = 4

- Substitute these value in the rule of the slope

∵ $m=\frac{4-3}{7-2}=\frac{1}{5}$

∴ the slope of the line is $m=\frac{1}{5}$

Let us substitute the value of the slope and the coordinates of point $(x_{1},y_{1})$ in the form of the equation

∵ $y-y_{1}=m(x-x_{1})$

∵ $x_{1}$ = 2 and $y_{1}$ = 3

∵ $m=\frac{1}{5}$

∴ $y-3=\frac{1}{5}(x-2)$

The point-slope equation of the line is $y-3=\frac{1}{5}(x-2)$

Learn more:

You can learn more about the linear equation in brainly.com/question/12941985

#LearnwithBrainly

3 0

3 years ago

SOLVED

Nastasia [14]

5)
a. The equation that describes the forces which act in the x-direction:
 Fx = 200 * cos 30 

b. The equation which describes the forces which act in the y-direction: 
 Fy = 200 * sin 30 

c. The x and y components of the force of tension: 
 Tx = Fx = 200 * cos 30 
 Ty = Fy = 200 * sin 30 

d.Since desk does not budge, frictional force = Fx
= 200 * cos 30 

 Normal force = 50 * g - Fy
= 50 g - 200 * sin 30
____________________________________________________________
6) Let F_net = 0
a. The equation that describes the forces which act in the x-direction:
(200N)cos(30) - F_s = 0

b. The equation that describes the forces which act in the y-direction:
F_N - (200N)sin(30) - mg = 0

c. The values of friction and normal forces will be:
Friction force= (200N)cos(30),

The Normal force is not 490N in either case...
Case 1 (pulling up)
F_N = mg - (200N)sin(30) = 50g - 100N = 390N

Case 2 (pushing down)
F_N = mg + (200N)sin(30) = 50g + 100N = 590N

4 0

3 years ago

How do you write 76% as a fraction

padilas [110]

Answer:

76/100 or simplified into 19/25

4 0

3 years ago

This is very confusing

drek231 [11]

Answer:

13

Step-by-step explanation:

6 0

2 years ago

What is the zero in the quadratic function f(x)= 9x^2-54x-19?

Alex17521 [72]

Answer:

6.33... and 0.333...

Step-by-step explanation:

The quadratic formula is

$x=\frac{-b+\sqrt{b^2-4ac} }{2a}$ .

It is important because while some quadratics are factorable and can be solved not all are. The formula will solve all quadratic equations and can also give both real and imaginary solutions. Using the formula will require less work than finding the factors if factorable. We will substitute a=9, b=-54 and c=-19.

$x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}\\x=\frac{-(-54)+/-\sqrt{(-54)^2-4(9)(-19)} }{2(9)}\\x=\frac{54+/-\sqrt{2916+684} }{18}$

We will now solve for the plus and the minus.

The plus,,,

$x=\frac{54+\sqrt{3600}}{18}\\x=\frac{54+60}{18}\\x=\frac{114}{18}\\x=6.3$

and the minus...

$x=\frac{54-\sqrt{3600}}{18}\\x=\frac{54-60}{18}\\x=\frac{-6}{18}\\x=-0.333...$

8 0

3 years ago