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inna [77]
3 years ago
14

Write the equation in Slope-Intercept Form given these two points: (0,8) (-2,2)

Mathematics
1 answer:
In-s [12.5K]3 years ago
8 0

Answer:

y     = 3x + 8

Step-by-step explanation:

to find slope intercept if we have 2 points use this formula:

find the slope first: m= (y2-y1)/ (x2-x1)

after get the slope, use this formula:

y-y1 = m(x-x1)

Answer:

m= (y2-y1)/ (x2-x1)

  = (2-8)/ (-2-0)= -6/-2 = 3

y-y1 = m(x-x1)

y-8 = 3 (x-0)

y     = 3x + 8

hope it helps

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Streak
Monica [59]

Answer: Not 100% sure but this is what I think.

-4/5

Step-by-step explanation:

(5, -1) (15, −9)

1Y - 2Y / 1X - 2X = SLOPE

-1 + 9 / 5 - 15 = 8/-10 = -8/10 = -4/5

7 0
2 years ago
Suppose in the University of Manitoba, 40% of the students live in apartments. If 600 students are randomly selected, then the a
just olya [345]

Answer:

P(200\leq X\leq 400)=P(\frac{200-240}{12}\leq \frac{X-\mu}{\sigma}\leq \frac{400-240}{12})=P(-3.33\leq Z \leq 13.33)

=P(Z

So then the correct answer would be:

B) .9996

Step-by-step explanation:

The exact way to solve this problem is using the binomial distribution, assuming that our random variable of interest is "number of students living in apartments" represented by X and X \sim Bin(n=600, p =0.4)

And we want this probability:

P(200 \leq X \leq 400) [tex]In order to find this probability we can use the foloowing excel code:"=BINOM.DIST(400,600,0.4,TRUE)-BINOM.DIST(199,600,0.4,TRUE)"And we got:[tex] P(200 \leq X \leq 400) =0.999675[tex]But for this case the problem says that we need to approximate, so then we can use the normal approximation to the normal distribution. We need to check the conditions in order to use the normal approximation.
[tex]np=600*0.4=240\geq 10

n(1-p)=600*(1-0.4)=360 \geq 10

So we see that we satisfy the conditions and then we can apply the approximation.

If we appply the approximation the new mean and standard deviation are:

E(X)=np=600*0.4=240

\sigma=\sqrt{np(1-p)}=\sqrt{600*0.4(1-0.4)}=12

And then X \sim N (\mu = 240, \sigma= 12)

And we are interested on the following probability:

P(200\leq X\leq 400)=P(\frac{200-240}{12}\leq \frac{X-\mu}{\sigma}\leq \frac{400-240}{12})=P(-3.33\leq Z \leq 13.33)

=P(Z

So then the correct answer would be:

B) .9996

6 0
3 years ago
Given the first term and the common difference find the first five terms and the explicit formula
Zielflug [23.3K]

Answer:

a_{1} = -34,\: a_{2} = -44,\: a_{3} = -54,\: a_{4} = -64,\: a_{5} = -74

____________________________________

a_{n} = -34\:–\:10(n-1)

8 0
3 years ago
Write the equation for the line that passes through (3,4) and (2,-1) in slope intercept form
Lina20 [59]
Y=mx+b
m=4-1\3-2
3\1
y=3\1x+b
(u can take any of the 2 points.am taking the first one)
4=3\1(3)+b
4=9+b
4-9=b
-5=b
answer=
y=3\1x-5
5 0
2 years ago
A parallelogram has one angle that measures 118°. What are the measures of the other three angles in the parallelogram?
MariettaO [177]

Step-by-step explanation:

<em>Given</em>

<em>We </em><em>know </em><em>that </em><em>in </em><em>a </em><em>parallelogram </em><em>opposite </em><em>angles </em><em>are </em><em>equal</em><em>. </em><em>So </em>

<em>1st </em><em>and </em><em>3rd </em><em>angles </em><em>=</em><em> </em><em>1</em><em>1</em><em>8</em><em>°</em>

<em>Let </em><em>2nd </em><em>and </em><em>4th </em><em>angles </em><em>=</em><em> </em><em>x</em>

<em>Now</em>

<em>1</em><em>1</em><em>8</em><em>°</em><em> </em><em>+</em><em> </em><em>1</em><em>1</em><em>8</em><em>°</em><em> </em><em>+</em><em> </em><em>x </em><em>+</em><em> </em><em>x </em><em>=</em><em> </em><em>3</em><em>6</em><em>0</em><em>°</em><em> </em><em>(</em><em> </em><em>Being </em><em>sum </em><em>of </em><em>angles </em><em>of </em><em>parallelogram</em><em>) </em>

<em>2</em><em>3</em><em>6</em><em>°</em><em> </em><em>+</em><em> </em><em>2x </em><em>=</em><em> </em><em>3</em><em>6</em><em>0</em><em>°</em>

<em>2x </em><em>=</em><em> </em><em>3</em><em>6</em><em>0</em><em>°</em><em> </em><em>-</em><em> </em><em>2</em><em>3</em><em>6</em><em>°</em>

<em>2x </em><em>=</em><em> </em><em>1</em><em>2</em><em>4</em><em>°</em>

<em>Therefore </em><em>x </em><em>=</em><em> </em><em>6</em><em>2</em><em>°</em>

<em>Now </em><em>the </em><em>measure </em><em>of </em><em>other </em><em>all </em><em>angles </em>

<em>118</em><em>°</em><em> </em><em>,</em><em> </em><em>6</em><em>2</em><em>°</em><em> </em><em>,</em><em> </em><em>1</em><em>1</em><em>8</em><em>°</em><em>,</em><em> </em><em>6</em><em>2</em><em>°</em>

3 0
3 years ago
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