Answer:
-19
Step-by-step explanation:
2×2-2z4+y2-x2+z4
now we put the value,
4-2(2to the power 4)+(3 to the power 2)-(-4 to the power 2)+(2 to the power 4)
4-2×16+9-16+16
4-32+9
4+9-32
13-32
-19
please check the answer again i am sorry if it's wrong
Answer:
The bulbs should be replaced each 1060.5 days.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

How often should the bulbs be replaced so that no more than 1% burn out between replacement periods?
This is the first percentile, that is, the value of X when Z has a pvalue of 0.01. So X when Z = -2.325.




The bulbs should be replaced each 1060.5 days.
C is the answer hope this helps.
Answer:
103.95
Step-by-step explanation:
99×5/100=4.95
99+4.95=103.95
I think it would be <span>51 and 1/3, but I'm not sure</span>