Answer:
Option b. The value is a floating-point number that should be displayed with 2 decimal places.
Explanation:
The f is a format code for a floating point number. Sometimes, a specific precision is required to display a floating point number. To meet the precision requirement, we can precede the f with a dot and followed with a precision value.
For example:
print("My value: {0:.2f}".format(123.45678))
will display 123.46
*The output has been rounded up to two decimal places.
Answer:
Yes, Cross Industry Standard Process for Data Mining has six stages. Business understanding, data understanding, data preparation, modeling, evaluation, and deployment.
Explanation:
Answer:
Charles Babbage, an English mechanical engineer and polymath, originated the concept of a programmable computer. Considered the "father of the computer", he conceptualized and invented the first mechanical computer in the early 19th century.
Answer:
B
Explanation:
When you initialize an instance of FunEvent(tags, year) and assign it to bc. The instance variables in this case are: self.tags = ["g", "ml"] and self.year = 2022. But then you alter tags, which will also change self.tags, since self.tags is a reference to the list you passed in as an argument. This is not the case when you do year=2023 because, first of all, integers are not mutable, and also because even if somehow integers were mutable, you're not changing the object in-place, you're simply changing the where the "variable" is pointing to. So for example if you did tags = ["g", "ml", "bc"] instead of tags.append("bc"), it would also not change the value of the instance variable "tags", because you wouldn't be changing the object in-place. So when you print(bc), the instance variables will be ["g", "ml", "bc"] and 2022. When you try to print an object, it call try to convert it into a string using the __str__ magic method. In this case it will return a string formatted as "Event(tags={self.tags}, year={self.year}) which will output "Event(tags=['g', 'ml', 'bc'], year=2022)" So the correct answer is B
