What does the following code print?double[] myList = {1, 5, 5, 5, 5, 1};double max = myList[0];int indexOfMax = 0;for (int i = 1

Question

2 years ago

8

; i < myList.length; i++) { if (myList[i] >= max) { max = myList[i]; indexOfMax = i; }}System.out.println(indexOfMax);

1 answer:

Liula [17] · Answer 1 · 2022-07-27T21:29:19+03:00

Answer:

This code will print: 4

Explanation:

Following is the step-by-step explanation for the given code:

Given is the array of data type double named myList, it has entries, 1, 5, 5, 5,5, 1:

double[] myList = {1, 5, 5, 5, 5, 1};

Now the first element of the array (1) with index 0 will be stored in the variable max (data type double).

double max = myList[0];

int indexOfMax = 0;

Now for loop will be used to find the maximum number of the array. The variable i will be put as index for each element to compare with first element. If the checked element is greater than or equal to the integer in max, it will be replaced. So at the end the variable max will have value 5 that will be at index i = 4.

for (int i = 1; i < myList.length; i++)

{ if (myList[i] >= max)

{ max = myList[i];

Now the variable i that is the index for max value will be stored in the variable indexOfMax (indexOfMax = 4).

indexOfMax = i; }}

At end the value stored in variable indexOfMax will be printed, so 4 will be printed as output.

System.out.println(indexOfMax);

i hope it will help you!