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3 years ago

"the nimby syndrome presents itself when discussing"

1 answer:

7 0

<span>The NIMBY syndrome presents itself when discussing drug treatment, landfills and jails. NIMBY is an acronym for </span>“Not In My Back Yard.” Person with NIMBY resists unwanted development, such as manufacturing plants, prisons, power companies, or chemical companies in his or her own neighborhood or town. <span>Their state of mind is called Nimbyism. </span>

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One weakness of the fossil record is

kherson [118]

It can be C or D but I think the answer is D

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3 years ago

Are flowers counted as an asexual reproducer?

True [87]

Answer by YourHope:

Are flowers counted as an asexual reproducer?

It all depends on the flower. Flower plants are capable of sexual reproduction. However, they vary on whether they can reproduce both ways, or only sexually.

6 0

2 years ago

Read 2 more answers

Which of the following shows all of the tripeptides that can be formed from one molecule each of lysine (Lys), threonine (Thr),

Ierofanga [76]

Answer:

LysThrHis, LysHisThr, HisLysThr, HisThrLys, ThrLysHis, ThrHisLys

Explanation:

You easily combine the options for the tripeptide if you made a chart

Also you can calculate the posibilities with the factorial function in the calculatio (x!): 3*2*1 (you can multiplicate the number of amoniacids by the followed numbers until 1) = 6

7 0

2 years ago

Read 2 more answers

________ is the biological heritage (including physical characteristics such as one's skin color and associated traits) that peo

Whitepunk [10]

Answer: Race

Explanation: Race is a heritage that various and diverse group of people use to identify with each other. Race may include physical characteristics such as the skin color example the black race and other associated traits such as facial features and hair texture

4 0

2 years ago

A population is made up of individuals where 77 have the A1A1 genotype, 65 have the A1A2 genotype, and 123 have the A2A2 genotyp

lana [24]

Answer:

Frequency of allele A1- 0.41

Explanation:

In Hardy weinberg equilibrium,

P refers to the dominant allele

q refers to the recessive allele

The allele frequency will be p+q=1

The genotypic frequency is- P²+q²+2pq=1

P²= genotype of dominant trait ( A1A1)- 77

2pq= genotype of heterozygotes (2pq)- 65

q²= genotype of recessive trait (A2A2)- 123

Total number of offsprings= 77+ 65+ 123

= 265

Now to calculate allele frequency of A1=

$\dfrac{\text{number of A1A1 offspring}}{ \text{total number of offspring}}+\dfrac{1}{2}(\dfrac{\text{number of A1A2 offspring}}{\text{total number of offspring}})$

= 77/265 + 1/2( 65//265)

= 0.290+ 0.122

= 0.413

Thus, 0.41 is correct.

3 0

3 years ago