Ask question

Ask question

All categories

2 years ago

15

Why is it important to learn algebraic expressions? How will we use them for everyday life?

1 answer:

Anna11 [10]2 years ago

5 0

People who cook, either professionally or for personal use, use simple algebraic expressions to adjust the ingredients in a dish depending on the number of servings desired. Medical professionals use algebra in a variety of applications, such as determining drug dosage and measuring the performance of body functions, such as cardiac output.

You might be interested in

What is the length of side x in the above right triangle

nataly862011 [7]

Answer:

its answer will be 9.first by using phythagorus theorem h^2=p^2+b^2'then h=15,p=12and b=x. again by putting the values of h ,p and b we get ,(15)^2=(12)^2+x^2. 225=144+x^2, x^2=225-144, x^2=81,x=√81,x=9 answer

7 0

3 years ago

1. Find the volume of the pyramid.<br> 5 in<br> 11 in<br> 9 in<br> 74

Oduvanchick [21]

The volume of the pyramid with the given length, width and height is 165in³.

<h3>What is the volume of the pyramid?</h3>

The volume of a right rectangular pyramid is expressed as;

V = ( L × W × H ) / 3

Given that;

Length L = 11in
Width W = 9in
Height H = 5in

We substitute into the equation above.

V = ( L × W × H ) / 3

V = ( 11in × 9in × 5in ) / 3

V = 495in³ / 3

V = 165in³

The volume of the pyramid with the given length, width and height is 165in³.

Learn more about volume of pyramid here: brainly.com/question/17615619

#SPJ1

5 0

1 year ago

Jeff, bill and Bernard are the three wealthiest people in the word. They share 80billion in the ratio 4:3:1 how much does bill g

Mumz [18]

Answer:

answer

Step-by-step explanation:

step by step explanation

8 0

3 years ago

How many solutions does the equation have, x1 + x2 + x3 = 10 , where x1 , x2, and x3 are non-negative integers?

MAVERICK [17]

Non-negative integers are positive integers or zero.

1. When $x_1=0,$ then there are such possible cases for $x_2$ and $x_3:$

$x_2=0,\ x_3=10;$
$x_2=1,\ x_3=9;$
$x_2=2,\ x_3=8;$
$x_2=3,\ x_3=7;$
$x_2=4,\ x_3=6;$
$x_2=5,\ x_3=5;$
$x_2=6,\ x_3=4;$
$x_2=7,\ x_3=3;$
$x_2=8,\ x_3=2;$
$x_2=9,\ x_3=1;$
$x_2=10,\ x_3=0.$

In total 11 solutions for $x_1=0.$

2. For $x_1=1,$ there are such possible cases for $x_2$ and $x_3:$

$x_2=0,\ x_3=9;$
$x_2=1,\ x_3=8;$
$x_2=2,\ x_3=7;$
$x_2=3,\ x_3=6;$
$x_2=4,\ x_3=5;$
$x_2=5,\ x_3=4;$
$x_2=6,\ x_3=3;$
$x_2=7,\ x_3=2;$
$x_2=8,\ x_3=1;$
$x_2=9,\ x_3=0.$

In total 10 solutions for $x_1=1.$

3. This process gives you

for $x_1=2$ - 9 solutions;
for $x_1=3$ - 8 solutions;
for $x_1=4$ - 7 solutions;
for $x_1=5$ - 6 solutions;
for $x_1=6$ - 5 solutions;
for $x_1=7$ - 4 solutions;
for $x_1=8$ - 3 solutions;
for $x_1=9$ - 2 solutions;
for $x_1=10$ - 1 solution.

4. Add all numbers of solutions:

$11+10+9+8+7+6+5+4+3+2+1=66.$

Answer: there are 66 possible solutions (with non-negative integer variables)

8 0

3 years ago

Read 2 more answers

And this one too please and thank u.

inn [45]

Answer:

$( - 4 \\ - 3$

Step-by-step explanation:

4unity to the left

3unity down

8 0

3 years ago