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3 years ago

Simplify the expression 4x+3(5y−x)

2 answers:

5 0

4x+3(5y-x)
Start by multiplying out the brackets
4x+15y-3x
Collect like terms
4x-3x+15y
Subtract the x's
X+15y
Hope this helps!

kipiarov [429]3 years ago

3 0

4x+3 (5y-x)

4x+15y-3x
X+15y

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Round 1.7802 to 1 significant figure

tiny-mole [99]

Answer:

It would be 2

Step-by-step explanation:

Since they are looking for only 1 significant fig. you would round the number that would make this correct, for example:

You would look at 1.7 and ignore the others...

7 is greater than 5 so it'll affect the 1

And that how you get 2 : )

3 0

2 years ago

Which zero pair could be added to the function so that the function can be written in vertex form?

Oduvanchick [21]

The function in this problem should be: f(x) =x² + 12x + 6

y = x² + 12x + 6
y - 6 = x² + 12x

x² ⇒ x * x
12x ⇒ 2*6*x
missing number is 6² = 36

y - 6 + 36 = x² + 12x + 36

(x+6)(x+6) ⇒ x(x+6)+6(x+6) ⇒ x² + 6x + 6x + 36 = x² + 12x + 36

y + 30 = x² + 12x + 36
y = (x+6)² - 30

Choice is D. 36,-36

5 0

3 years ago

C. Brian saves some money from his allowance to buy Mother a gift. His daily allowance is P50.00

Finger [1]

Answer:

1.thursday

his expenses was p26.85

2.monday he spent p40.8

3.18.90+23.15+11.80+16.35+9.20=approximately p55.6×30 days=p1,668

4.693.80-1,668

so he savings is completely enough

8 0

2 years ago

in a standard casino dice game the roller wins on the first roll if he rolls a sum of 7 or 11. what is the probability of winnin

Alborosie

Answer-

The probability of winning on the first roll is 0.22

Solution-

As in the game of casino, two dice are rolled simultaneously.

So the sample space would be,

$|S|=6^2=36$

Let E be the event such that the sum of two numbers are 7, so

E = {(1,6), (2,5), (3,4), (4,3), (5,2), (6,1)}

$|E|=56$

$\therefore P(E)=\dfrac{|E|}{|S|}=\dfrac{6}{36}$

Let F be the event such that the sum of two numbers are 11, so

F = {(6,5), (5,6)}

$|F|=2$

$\therefore P(F)=\dfrac{|F|}{|S|}=\dfrac{2}{36}$

Now,

$P(\text{sum is 7 or 11)}=P(E\ \cup\ F)=P(E)+P(F)=\dfrac{6}{36}+\dfrac{2}{36}=\dfrac{8}{36}=\dfrac{2}{9}=0.22$

8 0

3 years ago

At an ocean-side nuclear power plant, seawater is used as part of the cooling system. This raises the temperature of the water t

grandymaker [24]

Answer:

(a1) The probability that temperature increase will be less than 20°C is 0.667.

(a2) The probability that temperature increase will be between 20°C and 22°C is 0.133.

(b) The probability that at any point of time the temperature increase is potentially dangerous is 0.467.

Step-by-step explanation:

Let X = temperature increase.

The random variable X follows a continuous Uniform distribution, distributed over the range [10°C, 25°C].

The probability density function of X is:

$f(X)=\left \{ {{\frac{1}{25-10}=\frac{1}{15};\ x\in [10, 25]} \atop {0;\ otherwise}} \right.$

(a1)

Compute the probability that temperature increase will be less than 20°C as follows:

$P(X$

Thus, the probability that temperature increase will be less than 20°C is 0.667.

(a2)

Compute the probability that temperature increase will be between 20°C and 22°C as follows:

$P(20$

Thus, the probability that temperature increase will be between 20°C and 22°C is 0.133.

(b)

Compute the probability that at any point of time the temperature increase is potentially dangerous as follows:

$P(X>18)=\int\limits^{25}_{18}{\frac{1}{15}}\, dx\\=\frac{1}{15}\int\limits^{25}_{18}{dx}\,\\=\frac{1}{15}[x]^{25}_{18}=\frac{1}{15}[25-18]=\frac{7}{15}\\=0.467$

Thus, the probability that at any point of time the temperature increase is potentially dangerous is 0.467.

(c)

Compute the expected value of the uniform random variable X as follows:

$E(X)=\frac{1}{2}[10+25]=\frac{35}{2}=17.5$

Thus, the expected value of the temperature increase is 17.5°C.

7 0

3 years ago