Speed (S) = Distance (D) / time (t)
First stretch
45 = D / 2
D = 45*2
D = 90 mp
How is the same distance:
Second stretch
S = 90 / t
Average speed (AS):
AS = (S1+S2) / 2
60 = [45+(90/t)] / 2
120 = 45+90/t
120-45 = 90/t
75 = 90/t
t = 90/75
t = 1,2 h
________________________
And now:
S = 90 / t
S = 90 / 1,2
S = 75 mph
Answer:
yes
option 1
Step-by-step explanation:
Answer:
i need help with something like that aswell
Step-by-step explanation:
Answer:
B. isosceles triangle
Step-by-step explanation:
Answer:
Step-by-step explanation:
A circle is inscribed in an equilateral triangle PQR with centre O. If angle OQR = 30°, what is the perimeter of the triangle?
This is a circle inscribed in an equilateral triangle with side s.
If you are asking for the perimeter of PQR, it is 3s.
If you are asking for the perimeter of OQR, it is (3+23–√3)s
Since OR and SR are the hypotenuses of right triangles with adjacent side equal to ½ s, their length is ½s / cos 30° = (√3) /3.
(3/3)s + ((√3) /3)s + ((√3) /3)s = ((3 + 2√3)/3)s ≈ 2.1547s
Hope it helps
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