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3 years ago

Please help

Mathematics

2 answers:

Tems11 [23]3 years ago

8 0

The answer is (x+2)^2+(y+2)^2=16

svp [43]3 years ago

5 0

Answer:

(x + 2)^2 + (y + 2)^2 = 16

Step-by-step explanation:

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There are 7800 grams of lodine that have a half-life of 8 days. How much lodine will remain after 40 days?

anygoal [31]

Given that we know the initial mass of Iodine and its half-life, we want to see how much will remain after 40 days.

After 40 days, 244.17 grams of Iodine will remain.

<h3 /><h3>The half-life of materials and how to use it:</h3>

The half-life of a material is the time it takes for that amount of material to reduce to its half.

We can model the amount of Iodine as:

A(t) = A*e^{k*t}

Where A is the initial amount, in this case, 7800g.
k is a constant that depends on the half-life.
t is the time in days.

Replacing what we know, we get:

A(t) = 7800g*e^{k*t}

Now we use the fact that the half-life is 8 days, this means that:

e^{k*8} = 1/2

ln(e^{k*8}) = ln(1/2)

k*8 = ln(1/2)

k = ln(1/2)/8 = -0.0866

Then the function is:

A(t) = 7800g*e^{-0.0866*t}

So now we just need to evaluate this in t = 40.

A(40) = 7800g*e^{-0.0866*40} = 244.17g

So, after 40 days, 244.17 grams of Iodine will remain.

If you want to learn more about half-life and decays, you can read:

brainly.com/question/11152793

3 0

2 years ago

A different species of cockroach has weights that are approximately Normally distributed with a mean of 50 grams. After measurin

Ratling [72]

Answer:

The standard deviation of weight for this species of cockroaches is 4.62.

Step-by-step explanation:

Given : A different species of cockroach has weights that are approximately Normally distributed with a mean of 50 grams. After measuring the weights of many of these cockroaches, a lab assistant reports that 14% of the cockroaches weigh more than 55 grams.

To find : What is the approximate standard deviation of weight for this species of cockroaches?

Solution :

We have given,

Mean $\mu=50$

The sample mean x=55

A lab assistant reports that 14% of the cockroaches weigh more than 55 grams.

i.e. P(X>55)=14%=0.14

The total probability needs to sum up to 1,

$P(X\leq 55)=1-P(X>55)$

$P(X\leq 55)=1-0.14$

$P(X\leq 55)=0.86$

The z-score value of 0.86 using z-score table is z=1.08.

Applying z-score formula,

$z=\frac{x-\mu}{\sigma}$

Where, $\sigma$ is standard deviation

Substitute the values,

$z=\frac{x-\mu}{\sigma}$

$1.08=\frac{55-50}{\sigma}$

$1.08=\frac{5}{\sigma}$

$\sigma=\frac{5}{1.08}$

$\sigma=4.62$

The standard deviation of weight for this species of cockroaches is 4.62.

4 0

3 years ago

Which expression can be used to model the statement “On Wednesday, Nathaniel earned $10 less than he earned on Tuesday”?

Nostrana [21]

Answer:

n mimus 10

Explicacion paso a paso:

6 0

3 years ago

Read 2 more answers

What is the estimate of 119÷23.3

Crank

Your answer would be 5.10... Hope this helps :)

6 0

3 years ago

Question:

Allisa [31]

We know that 24 is 160% more than some recommended number, let's call it "x." This means 1.6 times the recommended number equals 24. Therefore, all we need to do is solve for x.

$1.6x=24$

$x=\frac{24}{1.6}$

Make sense?

4 0

3 years ago