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Y_Kistochka [10]
3 years ago
13

PLEASE HELP ASAP THANKS

Mathematics
1 answer:
Rasek [7]3 years ago
6 0
The last one is the correct answer choice.
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Q : <br> what 1:9 x 6 = ?
kow [346]

Answer:

the answer is \frac{2}{3}

Step-by-step explanation:

hope this helps :)

can I get brainliest plz

4 0
2 years ago
Read 2 more answers
14 divided by 3/8 ? (The question mark is not part of the problem...neither is this..)
dmitriy555 [2]
3 divided by 8 is .375
14 divided by .375 is 37.3 repeating
and the fraction for that is 112/3

4 0
3 years ago
Read 2 more answers
What does 1+4c=7+2c equal
stiv31 [10]

Answer:

c=3

Step-by-step explanation:

First simplify like terms.

1+4c=7+2c

1+2c=7 (subtract 2c from both sides)

2c=6 (subtract 1 from both sides)

c=3 (divide by 2)

CHECK:

1+4(3)=7+2(3)

1+12=7+6

13=13

Yes!

7 0
3 years ago
Read 2 more answers
The number of people arriving for treatment at an emergency room can be modeled by aPoisson process with a rate parameter of 5/h
saveliy_v [14]

Answer:

(a) The probability of having exactly four arrivals during a particular hour is 0.1754.

(b) The probability that at least 3 people arriving during a particular hour is 0.7350.

(c) The expected arrivals in a 45 minute period (0.75 hours) is 3.75 arrivals.

Step-by-step explanation:

(a) If the arrivals can be modeled by a Poisson process, with λ = 5/hr, the probability of having exactly four arrivals during a particular hour is:

P(X=4)=\frac{\lambda^{X}*e^{-\lambda}  }{X!} =\frac{5^{4}*e^{-5}  }{4!}=\frac{625*0.006737947}{24} =\frac{4.211}{24}=0.1754

The probability of having exactly four arrivals during a particular hour is 0.1754.

(b) The probability that at least 3 people arriving during a particular hour can be written as

P(X>3)=1-P(X\leq3)=1- (P(0)+P(1)+P(2)+P(3))

Using

P(X)=\frac{\lambda^{X}*e^{-\lambda}  }{X!}

We get

P(X>3)=1-P(X\leq3)=1- (P(0)+P(1)+P(2)+P(3))\\P(X>3)=1-(0.0067+ 0.0337+ 0.0842 + 0.1404 )\\P(X>3)=1-0.2650=0.7350\\

The probability that at least 3 people arriving during a particular hour is 0.7350.

(c) The expected arrivals in a 45 minute period (0.75 hours) is

EV=\lambda*t=5*0.75=3.75

8 0
2 years ago
Let f(x)= x^2 -2x+6 find f(-1)
Leokris [45]

Answer:

Step-by-step explanation:

f(x) = x^2 - 2x + 6

to find f(-1), we sub in -1 for every x

f(-1) = (-1^2) - 2(-1) + 6

f(-1) = 1 + 2 + 6

f(-1) = 9 <=======

8 0
3 years ago
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