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jek_recluse [69]
3 years ago
7

Can a radical ever be rational?

Mathematics
2 answers:
Vlad [161]3 years ago
4 0
A radical can sometimes be radical, if the number under it was a square root. Some examples include radical 9, which would simplify to 3, and radical 64, which would simplify to 8. 
yawa3891 [41]3 years ago
3 0

Answer:

The right answer is yes, sometimes a radical can be rational.

Step-by-step explanation:

In theory a radical is a number with the next form: \sqrt[n]{x}, the radicals can be rationals when x is written as zn, where z is an integer.

an example of a rational number that can be a radical is \sqrt[3]{125}=5

this is because 125 is a perfect third power of 5 and can be expressed as 5^{3}, and since 5 is an integer we can say is a rational.

another example is \sqrt[3]{8}

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jek_recluse [69]
<h3>Answer: Choice D</h3>

(f \circ g)(x) = x+12

Domain = [-3, infinity)

==================================================

Work Shown:

f(x) = x^2 + 9\\\\f(g(x)) = (g(x))^2 + 9\\\\f(g(x)) = (\sqrt{x+3})^2 + 9\\\\f(g(x)) = x+3 + 9\\\\f(g(x)) = x+12\\\\(f \circ g)(x) = x+12\\\\

In step 2, we replaced every x with g(x)

In step 3, we plugged in g(x) = sqrt(x+3)

The domain of g(x) is [-3, infinity), so this is the domain of (f \circ g)(x) as well since the composite function depends entirely on g(x). Put another way: the input of f(x) depends on the output of g(x), so that's why the domains match up.

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Simplify the following expression:<br> (x^3 y^4 z^2) (y^4 z^6 x^4)
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