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2 years ago

Can a radical ever be rational?

2 answers:

4 0

A radical can sometimes be radical, if the number under it was a square root. Some examples include radical 9, which would simplify to 3, and radical 64, which would simplify to 8.

yawa3891 [41]2 years ago

3 0

Answer:

The right answer is yes, sometimes a radical can be rational.

Step-by-step explanation:

In theory a radical is a number with the next form: $\sqrt[n]{x}$ , the radicals can be rationals when x is written as zn, where z is an integer.

an example of a rational number that can be a radical is $\sqrt[3]{125}=5$

this is because 125 is a perfect third power of 5 and can be expressed as $5^{3}$ , and since 5 is an integer we can say is a rational.

another example is $\sqrt[3]{8}$

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Such is biger 4/8 or 4/6

MArishka [77]

If you are asking which is bigger then it is 4/6

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3 years ago

The lengths of lumber a machine cuts are normally distributed with a mean of 106 inches and a standard deviation of 0.3 inch. (

Vinvika [58]

Answer:

a) $P(X>106.11)=P(\frac{X-\mu}{\sigma}\frac{106.11-106}{0.3})=P(z>0.37)$

And we can find this probability with the complement rule:

$P(z>0.37)=1-P(z$

b) $z =\frac{106.11- 106}{\frac{0.3}{\sqrt{44}}}= 2.431$

And if we use the z score we got:

$P(z>2.431) =1-P(z$

Step-by-step explanation:

Let X the random variable that represent the lengths of a population, and for this case we know the distribution for X is given by:

$X \sim N(106,0.3)$

Where $\mu=106$ and $\sigma=0.3$

Part a

We are interested on this probability

$P(X>106.11)$

And we can use the z score formula given by:

$z=\frac{x-\mu}{\sigma}$

And using this formula we got:

$P(X>106.11)=P(\frac{X-\mu}{\sigma}\frac{106.11-106}{0.3})=P(z>0.37)$

And we can find this probability with the complement rule:

$P(z>0.37)=1-P(z$

Part b

For this case we select a sample of n =44 and the new z score formula is given by:

$z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score we got:

$z =\frac{106.11- 106}{\frac{0.3}{\sqrt{44}}}= 2.431$

And if we use the z score we got:

$P(z>2.431) =1-P(z$

6 0

2 years ago

Determine which of the indicated column vectors are eigenvectors of the given matrix

gladu [14]

]Eigenvectors are found by the equation $(A-\lambda I) \vec{v} = 0$$ implying that $\det(A-\lambda I) = 0$ . We then can write:

$A-\lambda I = \left [ \begin{array}{cc} 4-\lambda & 2 \\ 5 & 1-\lambda \end{array}\right ]$

And:

$\det(A-\lambda I) = (4-\lambda)(1-\lambda) - 10 = 0$

Gives us the characteristic polynomial:

$\lambda^2 - 5 \lambda -6 = 0 \implies \lambda_1 = -1, \lambda_2 = 6$

So, solving for each eigenvector subspace:

$\left [ \begin{array}{cc} 4 & 2 \\ 5 & 1 \end{array} \right ] \left [ \begin{array}{c} x \\ y \end{array} \right ] = \left [ \begin{array}{c} -x \\ -y \end{array} \right ]$

Gives us the system of equations:

$4x + 2y = -x \newline 5x + y = - y$

Producing the subspace along the line $y = -\frac{5}{2} x$

We can see then that 3 is the answer.

7 0

3 years ago

Rafael has 3 times as many blue marbles as he does red marbles . He has a total of 124 marbles. How many read marbles and how ma

34kurt

<span>A quarter of the marbles are red, so there are 124/4 = 31 red marbles. The rest are blue, so there are 124 - 31 = 93 blue marbles.</span>

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3 years ago

Who got the answers for lib arts 1 flvs 1.07??

aleksklad [387]

Answer:

is the answer is 1.07 to 7.0

Step-by-step explanation:

8 0

2 years ago