Let number of boys be = b , number of girls = b + 4 . As total students = 20 b + b + 4 = 20 → 2b + 4 = 20 → 2b = 20 - 4 = 16 → b = 16 / 2 = 8 (boys) , so girls = 12

Prob (a random first child is a boy) = boys / total students = 8 c 1 / 20 c1, or = 8 / 20 = 0.4

Prob ( a 'Tina' out of two Tina is the last) = 2 c 1 / 20 c 1 , or = 2 / 20 = 0.1

8 0

2 years ago

Help me to solve this

antoniya [11.8K]

The answer is 2cm

$8 \times 10 {}^{ - 3} \times 250 = 2000 \times 10 {}^{ - 3} \\ = 2$
or:
$8 \times {10}^{ - 3} \times 250 = 0.008 \times 250 \\ = 2$

good luck

4 0

3 years ago

Find the midpoint between P(-5, -3) and Q(-2,8).(4 Points)​

Find the midpoint between P(-5, -3) and Q(-2,8).(4 Points)