Answer:
g-x=3
Step-by-step explanation:
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I hope this help...
—> And the answer is letter A
Let the weight of Paula's dog be x
Let the weight of Carla's dog be y
We know that the weight of Paula's dog is 3 times that of Carla's dog, therefore:
x = 3y ...........> equation I
We also know that the sum of the weights is 48 pounds, therefore:
x + y = 48 ............> equation II
Substitute with equation I in equation II:
3y + y = 48
4y = 48
y = 12 pouds
Substitute with the value of y in equation I:
x = 3(12) = 36 pounds
Based on the above calculations:
Paula's dog weighs 36 pounds
Carla's dog weighs 12 pounds
<h3>
Answer: Choice A) 0.20</h3>
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Explanation:
Let's say there are 1000 students. The students must take math, science or they can take both simultaneously.
- 65% of them are in math. So there are 0.65*1000 = 650 math students.
- 43% are in science, leading to 0.43*1000 = 430 science students.
- 13% are in both so we have 0.13*1000 = 130 students who are in both.
Now onto the sentence that says "Suppose a high school student who is enrolled in a math class is selected at random"
This means we only focus on the 650 math students and ignore the 1000-650 = 350 students who aren't in math.
Of those 650 math students, 130 are also in science (since 130 are in both classes).
The probability we're after is therefore 130/650 = 0.20
