For this case the first thing we must observe is that the mass increases 0.4 grams when the diameter increases 1 millimeter.
Therefore, the slope of the line is given by:
m = 0.4
Thus, the function that best suits the table is given by:
f (x) = -4 + 0.4x
For example, for x = 20 we have:
f (20) = -4 + 0.4 (20)
f (20) = -4 + 8
f (20) = 4
The result, matches the table.
Answer:
The function that is best represented by the scatter plot is:
f (x) = -4 + 0.4x

6 0

3 years ago

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If the exponent is 3 and the base is 2 whats the simplified expression

Rom4ik [11]

If the base is 2 and the exponent is the the expression would look like this → 2³. In order to simplify it, you have to multiply the base number by the number of the exponent.

2×2×2=8
Therefore, the simplified expression would be 8.

I hope this helped.

3 0

3 years ago

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The value of which of these expressions is closest to e?

mars1129 [50]

Answer:

Step-by-step explanation:

Given: expressions

To find: the expression whose value is closest to e

Solution:

Value of e is 2.718

$\left ( 1+\frac{1}{19} \right )^{19}=\left ( \frac{20}{19} \right )^{19}=2.65\\\left ( 1+\frac{1}{22} \right )^{22}=\left ( \frac{23}{22} \right )^{22}=2.659\\\left ( 1+\frac{1}{20} \right )^{20}=\left ( \frac{21}{20} \right )^{20}=2.653\\\left ( 1+\frac{1}{21} \right )^{21}=\left ( \frac{22}{21} \right )^{21}=2.656$

Therefore, value 2.659 is closest to the value of e.

So, option B. is correct.

7 0

3 years ago

A circular swimming pool has a radius of 28ft. There is a path all the way around the pool that's 4ft wide. A fence is going to

Natalka [10]

Answer:

Therefore 200.96 ft.of fencing are needed to go around the pool path.

Step-by-step explanation:

Given, a circular swimming pool has a radius of 28ft. There is a path all the way around the pool. The width of the path 4 ft.

The radius of the outside edge the pool path is

= Radius of the pool + The width of the path

= (28+4) ft

= 32 ft.

To find the length of fencing, we need to find the circumference of outside the pool path.

Here r= 32 ft

The circumference of outside edge of the pool path

= $2\pi r$

$=(2\times 3.14 \times 32) ft$

=200.96 ft.

Therefore 200.96 ft.of fencing are needed to go around the pool path.

3 0

3 years ago