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Eva8 [605]
3 years ago
7

Olivia's mom is ordering cupcakes for Olivia's birthday. A pack of 6 cupcakes from Baked Fresh costs $18. A pack of 12 cupcakes

from Milk 'n' Creme Bakery costs $37.20. How much more does Milk 'n' Creme Bakery charge per cupcake?
Mathematics
2 answers:
leva [86]3 years ago
7 0
Answer: milk ‘n’ creme charges 10 more cents than baked fresh per cupcake
you want to find the unit rate for each cupcake to find out how much more they charge.
first for baked fresh you would do $18/6 cupcakes to get $3 per cupcake, giving you a unit rate of 3
then for milk ‘n’ creme you would do $37.20/12 cupcakes to get $3.10 per cupcake, giving you a unit rate of 3.1
the difference will be found by subtracting the two to get 10 cents difference.
hope this helps !
sergejj [24]3 years ago
4 0

Answer:

10 cents more

Step-by-step explanation:

37.20/12=3.1

18/6=3

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B. y = -6

Step-by-step explanation:

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artcher [175]

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4 0
3 years ago
Help whit that 3 questions please and thanks
Serjik [45]

Answer:

80.

4s+5c=46\\3s+c=22

81. Each apple cost $0.50

82. One pound of chocolate = $3

Step-by-step explanation:

80.

Let sold of 1 senior citizen ticket be "s", and

cost of 1 child ticket be "c"

First Day, 4 senior citizen ticket and 5 child tickets sold, equaled $46, so the equation we can write is:

4s+5c=46

Second Day, 3 senior citizen ticket and 1 child ticket sold, equaled $22, so the equation we can write is:

3s+c=22

So, the system of equation (2 equations) written above can be solved simultaneously to find our answer.

4s+5c=46\\3s+c=22

81.

Let price of 1 apple be "a" and price of 1 banana be "b"

Since 3 apples and 2 banana cost $2, so we can write:

3a + 2b = 2

Then,

4 apples and 4 bananas cost $3, so we can write:

4a + 4b = 3

We can solve for the variable b in equation 1. Shown below:

3a + 2b = 2\\2b=2-3a\\b=\frac{2-3a}{2}

Now we put this value of b into equation 2 and solve for cost of 1 apple, a. Shown below:

4a+4b=3\\4a+4(\frac{2-3a}{2})=3\\4a+4-6a=3\\2a=1\\a=\frac{1}{2}\\a=0.5

So each apples cost $0.5

82.

Let 1 pound of chocolate be cost "c"

Let 1 pound of peanut be cost "p"

4 lb of chocolate and 2 lb of peanut = $16, thus we can write:

4c + 2p = 16

Next,

2 lb of chocolate and 3 lb of peanut costed $12, so we can write:

2c + 3p = 12

We solve first equation for p:

4c + 2p = 16\\2p=16-4c\\p=\frac{16-4c}{2}\\p=8-2c

Now, we put this expression for p into equation 2 and solve for c:

2c + 3p = 12\\2c + 3(8-2c) = 12\\2c+24-6c=12\\4c=12\\c=3

So, 1 pound of chocolates cost $3

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4 years ago
Combine the like terms to create an equivalent expression: r+(-5r)
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r + -5r

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3 years ago
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