Its the last one, the shapes but be polygons.
200 + 200 + 200 + 200 + 200 + 200 + 200 + 200 + 200 = 1,800
Answer:
3 tothe one it is the answer
Answer:
Angle CBE
Step-by-step explanation:
They share the same degree. Or are the same angle in a different place with a different name.
To find the time at which both balls are at the same height, set the equations equal to each other then solve for t.
h = -16t^2 + 56t
h = -16t^2 + 156t - 248
-16t^2 + 56t = -16t^2 + 156t - 248
You can cancel out the -16t^2's to get
56t = 156t - 248
=> 0 = 100t - 248
=> 248 = 100t
=> 2.48 = t
Using this time value, plug into either equation to find the height.
h = 16(2.48)^2 + 56(2.48)
Final answer:
h = 40.4736
Hope I helped :)
