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SVEN [57.7K]
3 years ago
5

Vector u has a magnitude of 5 units and a direction angle of 75°, and vector v has a magnitude of 6 units and a direction angle

of 210°. What is the component form of the vector u + v?
A.) < -3.95, 1.83>

B.) < -3.94, 1.89>

C.) < -3.90, 1.89>

D.) < -3.90, 1.83>
Mathematics
1 answer:
Fofino [41]3 years ago
3 0

Answer:

Option D is the correct answer.

Step-by-step explanation:

We have vector u = 5 ( cos 75 i + sin 75 j ) = 1.294 i + 4.830 j

Vector v = 6 ( cos 210 i + sin 210 j ) = -5.19 i - 3 j

u + v =  1.294 i + 4.830 j + (-5.19 i - 3 j) = -3.90 i + 1.83 j = < -3.90, 1.83>

Option D is the correct answer.

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Long division<br> 3x+1/6x^6+5x^5+2x^4-9x^3+7x^2-10x+2
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(6 x^{6}+5x^{5}+2x^{4}-9x^{3}+7x^{2}-10x+2) / (3x+1)

We divide first number from first parenthesis with first number from second parenthesis. Then the resulting number we multiply by all numbers in second parenthesis and substract from first parenthesis.

6 x^{6}/3x = 2 x^{5} \\  \\ 6 x^{6}+5x^{5}+2x^{4}-9x^{3}+7x^{2}-10x+2 - 6 x^{6} -2 x^{5} = 3x^{5}+2x^{4}-9x^{3}+7x^{2}-10x+2\\

We repeat previous steps until we run out of numbers:
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\frac{91}{9} x^{2}/3x=\frac{91}{27} x \\ \\ \frac{91}{9} x^{2}-10x+2-\frac{91}{9} x^{2}-\frac{91}{27} x= \\ \\ -\frac{361}{27} x+2 \\ \\ \\ -\frac{361}{27} x/3x=-\frac{361}{81} \\ \\ -\frac{361}{27} x+2+\frac{361}{27}x+\frac{361}{27}= \\ \\ \frac{415}{27}

We are left with a number that has no x inside. This is remainder.
The final solution is sum of all these solutions and remainder:
(2 x^{5}+x^{4}+\frac{1}{3} x^{3} - \frac{28}{9} x^{2} +\frac{91}{27} x)+(-\frac{361}{81} )
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