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olasank [31]
3 years ago
14

Help please!!!! Thanksss

Mathematics
1 answer:
Setler [38]3 years ago
6 0

Answer:

Correct option: E

Step-by-step explanation:

The group must have 1 man and 1 woman.

So, for the woman slot, we have 4 possible choices, because we have 4 women and 1 slot to occupy.

For the man slot, we have 2 possible choices, because we have 2 men and 1 slot to occupy.

So the number of different groups we can make is the product of the number of possibilities for each slot:

Number of groups = 4 * 2 = 8

Correct option: E

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A grocery store manager uses 1/2 crate of apples for every 3/4 crate if oranges in a fruit display. How many crates of oranges w
ludmilkaskok [199]

Answer:

15/4

Step-by-step explanation:

This is a proportion question

It says 1/2 crates of apple are used for every 3/4 crates of oranges

For 5/2 crates of apple, x crates of oranges will be needed.

To get x, we simply multiply 1/2 by x and equate it to 3/4 multiplied by 5/2

This means: 0.5x = 0.75 × 2.5

x = ( 0.75 × 2.5 ) ÷ 0.5 = 3.75

Hence for 5/2 crates for apple, she will need 15/4 crates of oranges.

8 0
3 years ago
Help me plzzzzzzzZzzzzz​
gizmo_the_mogwai [7]

Use order of operations.

-23-20-(-17)+(-5)x(-2)+4x5

Do all multiplication steps.

-23-20-(-17)+10+20

Do all addition and subtraction steps fro left to right.

-43-(-17)+10+20

-26+10+20

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answer: 4

8 0
3 years ago
Help me anyone ASAP snens
azamat

Answer:

thousandths

Step-by-step explanation:

5 0
3 years ago
The probability that your call to a service line is answered in less than 30 seconds is 0.75. Assume that your calls are indepen
vfiekz [6]

Answer:

a) 0.2581

b) 0.4148

c) 17

Step-by-step explanation:

For each call, there are only two possible outcomes. Either they are answered in less than 30 seconds. Or they are not. The probabilities for each call are independent. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

p = 0.75

a. If you call 12 times, what is the probability that exactly 9 of your calls are answered within 30 seconds? Round your answer to four decimal places (e.g. 98.7654).

This is P(X = 9) when n = 12. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 9) = C_{12,9}.(0.75)^{9}.(0.25)^{3} = 0.2581

b. If you call 20 times, what is the probability that at least 16 calls are answered in less than 30 seconds? Round your answer to four decimal places (e.g. 98.7654).

This is P(X \geq 16) when n = 20

So

P(X \geq 16) = P(X = 16) + P(X = 17) + P(X = 18) + P(X = 19) + P(X = 20)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 16) = C_{20,16}.(0.75)^{16}.(0.25)^{4} = 0.1897

P(X = 17) = C_{20,17}.(0.75)^{17}.(0.25)^{3} = 0.1339

P(X = 18) = C_{20,18}.(0.75)^{18}.(0.25)^{2} = 0.0669

P(X = 19) = C_{20,19}.(0.75)^{19}.(0.25)^{1} = 0.0211

P(X = 20) = C_{20,20}.(0.75)^{20}.(0.25)^{0} = 0.0032

So

P(X \geq 16) = P(X = 16) + P(X = 17) + P(X = 18) + P(X = 19) + P(X = 20) = 0.1897 + 0.1339 + 0.0669 + 0.0211 + 0.0032 = 0.4148

c. If you call 22 times, what is the mean number of calls that are answered in less than 30 seconds? Round your answer to the nearest integer.

The expected value of the binomial distribution is:

E(X) = np

In this question, we have n = 22

So

E(X) = 22*0.75 = 16.5

The closest integer to 16.5 is 17.

7 0
3 years ago
The sum of the numbers as the product of their GCF and other sum so what is 32 plus 20???
densk [106]
I dont quite undeerstand but the gcf for both are..., if that helps is 4 because
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