Answer:
Step-by-step explanation:
DE given is
y''+8y'+15y=0, y(0)=0, y'(0)=1
Take Laplace on the DE
We get
Simplify to get
Y(s) = ![\frac{1}{2}[ {\frac{1}{s+3} -\frac{1}{s+5} }]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5B%20%7B%5Cfrac%7B1%7D%7Bs%2B3%7D%20-%5Cfrac%7B1%7D%7Bs%2B5%7D%20%7D%5D)
Take inverse
There are 63 students in the room, this is because 21 time 3 gives you 63.
The GCF we factor out is 4a
8ab = 4a*2b
16ac = 4a*4c
12a = 4a*3
Each term has been factored so that 4a is a factor
Using those factorizations, we can use the distributive property in reverse
8ab - 16ac + 12a = 4a*2b - 4a*4c + 4a*3
8ab - 16ac + 12a = 4a*(2b - 4c + 3)
Answer is choice A<span />
Answer:
Please if you don't mind, complete your question thanks
Answer:
4cm
Step-by-step explanation:
Given data
L=(2x+3)
W=(x-1)
P=28cm
A= L*W
A= (2x+3)*(x-1)
open bracket
A= 2x^2-2x+3x-3
collect like terms
A= 2x^2+x-3
P= 2L+2W
P= 2*(2x+3)+2(x-1)
P= 4x+6+2x-2
collect like terms
P= 6x-4
but p= 28
28= 6x-4
28-4= 6x
24= 6x
x= 24/6
x= 4cm
Hence x= 4cm
