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Verizon [17]
3 years ago
8

Hellppppppppppppppppp​

Mathematics
1 answer:
Dafna1 [17]3 years ago
5 0
1/5 since there’s 5 possibilities and one green
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Compatible numbers are easy to divide mentally.
hope this helped
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Convert 6 yards into meters. Round your answer to the nearest tenth.
Helga [31]

Answer:

5.4864

Step-by-step explanation:

to the nearest tenth probably 0.5

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3 years ago
I am supposed to be learning pie is there any good method for remembering it ​
KiRa [710]

Answer:

there is a video called the pi song

just basic value is 22/7 or 3.14

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3 years ago
Graph y=2/3x-4<br><br><br><br> i need help!!!!!
Irina18 [472]

Step-by-step explanation:

Y=2/3x-4 is in Slope - intercept form meaning you are shown the slope (how steep the line is) and the y intercept (where the equation hits the vertical axis)

With the given information, select the point (0, -4) on the graph, this is where the line crosses the y axis, as shown through the -4 in the equation.

Next, look at the slope and youll see 2/3x. Slope is in format "rise over run" meaning the first number (2) is the vertical change, so up two, and the second number (3) is horizontal change, right 3.

Combine these two steps together and select point (0. -4) then the next point should be at (3,2), 2 units up and three to the right from the y intercept.

4 0
3 years ago
Use spherical coordinates. Find the volume of the solid that lies within the sphere x^2 + y^2 + z^2 = 81, above the xy-plane, an
Natasha_Volkova [10]

Answer:

The volume of the solid is 243\sqrt{2} \ \pi

Step-by-step explanation:

From the information given:

BY applying sphere coordinates:

0 ≤ x² + y² + z² ≤ 81

0  ≤ ρ²   ≤   81

0  ≤ ρ   ≤  9

The intersection that takes place in the sphere and the cone is:

x^2 +y^2 ( \sqrt{x^2 +y^2 })^2  = 81

2(x^2 + y^2) =81

x^2 +y^2 = \dfrac{81}{2}

Thus; the region bounded is: 0 ≤ θ ≤ 2π

This implies that:

z = \sqrt{x^2+y^2}

ρcosФ = ρsinФ

tanФ = 1

Ф = π/4

Similarly; in the X-Y plane;

z = 0

ρcosФ = 0

cosФ = 0

Ф = π/2

So here; \dfrac{\pi}{4} \leq \phi \le \dfrac{\pi}{2}

Thus, volume: V  = \iiint_E \ d V = \int \limits^{\pi/2}_{\pi/4}  \int \limits ^{2\pi}_{0} \int \limits^9_0 \rho   ^2 \ sin \phi \ d\rho \   d \theta \  d \phi

V  = \int \limits^{\pi/2}_{\pi/4} \ sin \phi  \ d \phi  \int \limits ^{2\pi}_{0} d \theta \int \limits^9_0 \rho   ^2 d\rho

V = \bigg [-cos \phi  \bigg]^{\pi/2}_{\pi/4}  \bigg [\theta  \bigg]^{2 \pi}_{0} \bigg [\dfrac{\rho^3}{3}  \bigg ]^{9}_{0}

V = [ -0+ \dfrac{1}{\sqrt{2}}][2 \pi -0] [\dfrac{9^3}{3}- 0 ]

V = 243\sqrt{2} \ \pi

4 0
3 years ago
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